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3 years ago

A. To find the slope and intercept of an equation, the equation must be in _________________ form.

Mathematics

1 answer:

deff fn [24]3 years ago

7 0

1. Standard form
2.slope is 3/4
Y intercept is 0

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How would i solve these two problems?

Montano1993 [528]

Number 17 9216 because you take 96*4

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3 years ago

the diameters of Douglas firs grown at a Christmas tree farm are normally distributed with a mean of 4 inches and a standard dev

aksik [14]

Answer:

Proportion of the trees will have diameters between 2 and 6 inches = 0.8164

Step-by-step explanation:

Given -

Mean $(\nu )$ = 4

Standard deviation $(\sigma )$ = 1.5

Let X be the diameter of tree

proportion of the trees will have diameters between 2 and 6 inches =

$P(2< X< 6)$ = $P(\frac{2 - 4 }{1.5}< \frac{X - \nu }{\sigma}< \frac{6 - 4 }{1.5})$

= $P(\frac{-2 }{1.5}< Z< \frac{2 }{1.5})$ Put [ $Z = \frac{X - \nu }{\sigma}$ ]

= $P(-1.33< Z< 1.33)$

= $(Z< 1.33) - (Z< -1.33)$

= .9082 - .0918

= 0.8164

6 0

3 years ago

Show all steps!!!

Lunna [17]

$-\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|-\frac{2}{3}-2^3-\frac{2}{3}\left|-\frac{1}{2}\right|^3$
$\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|=\frac{1}{12}$
$\frac{2}{3}\left|-\frac{1}{2}\right|^3=\frac{1}{12}$
$=-\frac{1}{12}-\frac{2}{3}-2^3-\frac{1}{12}$
$=-\frac{53}{6}$

4 0

3 years ago

Volume of composite figures

Feliz [49]

<u>✍️</u><u>Answer:</u>

The volume of the figure is 381 cubic in

$v=L*W*H$

$v=(16)(7)(3)+1/2(3)(5)(6)$

$v=336+45$

$v=381 in^3$

✮✮✮✮✮✮✮✮✮

<u>hope it helps...</u>

<u>have a great day!!</u>

7 0

3 years ago

Simplify (square root 2)( square root of 2^3)

steposvetlana [31]

Answer:

$\large\boxed{(\sqrt2)(\sqrt{2^3})=4}$

Step-by-step explanation:

$(\sqrt2)(\sqrt{2^3})\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt{2\cdot2^3}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{2^{1+3}}=\sqrt{2^4}\\\\(1)=\sqrt{2^{2\cdot2}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(2^2)^2}\qquad\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=2^2=4\\\\(2)=\sqrt{2\cdot2\cdot2\cdot2}=\sqrt{16}=6\ \text{because}\ 4^2=16$

8 0

3 years ago