1. =
2.
3.q+4=-4
I don't know number 2
Keywords
system; linear equations; graphing; solution
we have
-------> equation A
----> equation B
The <u>system</u> of <u>linear equations</u> is composed of equation A and equation B
Substitute the equation B in equation A
![y=-\frac{5}{2}[4-2y]-7](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B5%7D%7B2%7D%5B4-2y%5D-7)
Find the value of x
![x=4-2[17/4]=-4.5](https://tex.z-dn.net/?f=x%3D4-2%5B17%2F4%5D%3D-4.5)
The<u> solution</u> is the point 
Using a <u>graphing</u> tool
see the attached figure
therefore
the answer is the option A
The answer would be 1.405332e-13
Hope I helped!
Answer:
x=-3 im pretty sure
Step-by-step explanation:
so if y=4 and 4 is something plus 7, 7+-3=4 so im abut 98% its -3
Trust me: You must know how to do this basic factoring yourself.
x^2 -5x - 6 factors into (x-6)(x+1). Note how I got that: -6 is the product of 1 and -6, and -6 + 1 = -5.
You could also factor this by grouping:
x^2 -5x - 6 = x(x-6) + 1(x-6). Note how the middle terms combine to produce -5x and how (x-6) is a factor common to both terms; this leaves (x+1). So the factors are (x-6)(x+1).
