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tekilochka [14]

3 years ago

7

Simplify 17d-5e+13d-7e

2 answers:

Katena32 [7]3 years ago

8 0

$17d-5e+13d-7e=30d-12e$

Naily [24]3 years ago

7 0

$17d-5e+13d-7e = (17d+13d)-(5e+7e)=\boxed {30d-12e}$

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13x = 15x - 8 <br><br> What is the value of X?

maw [93]

Answer:x equals 4

Step-by-step explanation:

8 0

3 years ago

When 2x^2 - 20x + 49 = 19 is written in the form (x - p)^2 = q, what is the value of q? Show your work please.

Strike441 [17]

= 2x^2 - 20x + 49 = 2(x^2 - 10x + 49/2)

y= 2((x-5)^2 - 25 + 49/2) = 2((x-5)^2 - 1/2) = 2(x-5)^2 - 1

q =5, r=-1, p=2

Vertex = (q,r) = (5,-1)

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3 years ago

Leann is 3 cm taller than Fred. If Fred's height is f cm, then Leann's height is cm?

jek_recluse [69]

F + 3 = leann's height

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3 years ago

The table shows a proportional relationship between the number of stars Roberto collects in a game and his total points. A row o

maks197457 [2]

Answer:

1) 20 stars; 30 points.

2) 28 stars, 42 points.

3) 38 stars, 57 points.

Step-by-step explanation:

<h3> The missing table is attached.</h3>

Let be "x" the numbers of stars Roberto collects and "y" his total points.

The proportional relationship has this form:

$y=kx$

Where "k" is the constant of proportionality.

We can choose the point $(8,12$ ) from the table, where:

$x=8\\y=12$

Substituting these values into $y=kx$ and solving for "k", we get:

$12=k(8)\\\\\frac{12}{8}=k\\\\k=1.5$

Knowing the value of "k", we determine that the following Numbers of stars and the Total points could be used as the missing values in the table:

1) For $x=20$ :

$y=(1.5)(20)=30$

2) For $x=28$ :

$y=(1.5)(28)=42$

3) For $x=38$ :

$y=(1.5)(38)=57$

4 0

3 years ago

Read 2 more answers

A random sample of 100 people was taken. Eighty of the people in the sample favored Candidate A. We are interested in determinin

riadik2000 [5.3K]

Answer:

Option b - not significantly greater than 75%.

Step-by-step explanation:

A random sample of 100 people was taken i.e. n=100

Eighty of the people in the sample favored Candidate i.e. x=80

We have used single sample proportion test,

$p=\frac{x}{n}$

$p=\frac{80}{100}$

$p=0.8$

Now we define hypothesis,

Null hypothesis $H_0$ : candidate A is significantly greater than 75%.

Alternative hypothesis $H_1$ : candidate A is not significantly greater than 75%.

Level of significance $\alpha=0.05$

Applying test statistic Z -proportion,

$Z=\frac{\widehat{p}-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}$

Where, $\widehat{p}=80\%=0.80$ and $p=75%=0.75$

Substitute the values,

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}$

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.1875}{100}}}$

$Z=\frac{0.05}{0.0433}$

$Z=1.1547$

The p-value is

$P(Z>1.1547)=1-P(Z$

$P(Z>1.1547)=1-0.8789$

$P(Z>1.1547)=0.1241$

Now, the p-value is greater than the 0.05.

So we fail to reject the null hypothesis and conclude that the A is not significantly greater than 75%.

Therefore, Option b is correct.

7 0

3 years ago