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zheka24 [161]
2 years ago
8

Lidia keeps eight cards with the picture of a tomato and four cards with the picture of a carrot on a table face down, so the pi

ctures are hidden. She mixes up the cards then turns over one card and finds the picture of a carrot on it. She removes this card from the table and turns over another card.
What is the probability that the card Lidia turns over has a carrot on it?

A. 3/12
B. 3/11
C. 7/12
D. 7/11

I need help
Mathematics
1 answer:
Jobisdone [24]2 years ago
6 0
The probability would be 3/12 so the correct answer is A.
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360 m is the answer........

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4. The reflecting dish of a parabolic microphone has a cross-section in the shape of a parabola. The microphone itself is placed
elixir [45]
Assume the parabola is placed on a graph where the x-axis is the top of the dish.
The vertex is then at (0,-30)  The x-intercepts or zeros are at (-30,0) and (30,0)

The equation of such parabola would be:
y = a(x+30)(x-30)
Plug in vertex to find value of 'a'
-30 = a(0+30)(0-30) \\  \\ a = \frac{-30}{(-30)(30)} = \frac{1}{30}

Now find the focus given that p = \frac{1}{4a}
p = \frac{1}{4(1/30)} = \frac{30}{4} = 7.5

Answer: the microphone should be placed 7.5 inches from vertex.
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3 years ago
A jar holds 42 yellow and 14 purple crayons. A crayon is pulled out of the jar at random and then placed back in the jar.
noname [10]
The purple crayons take up 1/4 of the crayons in the jar. To get the answer:
140/4 = 35
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3 years ago
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HELPPP ACELLUS ALGEBRA 2<br> Divide.<br> 3x^3 + 2x^2 – 3x + 54<br> /x + 3
il63 [147K]

Answer:

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Step-by-step explanation:

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The length of some fish are modeled by a von Bertalanffy growth function. For Pacific halibut, this function has the form L(t) =
Dafna1 [17]

Answer:

a) L'(t) = 34.416*e^(-0.18*t)

b) L'(0) = 34 cm/yr , L'(1) =29 cm/yr , L'(6) =12 cm/yr

c) t = 10 year                                          

Step-by-step explanation:

Given:

- The length of fish grows with time. It is modeled by the relation:

                                   L(t) = 200*(1-0.956*e^(-0.18*t))

Where,

L: Is length in centimeter of a fist

t: Is the age of the fish in years.

Find:

(a) Find the rate of change of the length as a function of time

(b) In this part, give you answer to the nearest unit. At what rate is the fish growing at age: t = 0 , t = 1, t = 6

c) When will the fish be growing at a rate of 6 cm/yr? (nearest unit)

Solution:

- The rate of change of length of a fish as it ages each year  can be evaluated by taking a derivative of the Length L(t) function with respect to x. As follows:

                             dL(t)/dt = d(200*(1-0.956*e^(-0.18*t))) / dt

                             dL(t)/dt = 34.416*e^(-0.18*t)

- Then use the above relation to compute:

                            L'(t) = 34.416*e^(-0.18*t)

                            L'(0) = 34.416*e^(-0.18*0) = 34 cm/yr

                            L'(1) = 34.416*e^(-0.18*1) = 29 cm/yr

                            L'(6) = 34.416*e^(-0.18*6) = 12 cm/yr

- Next, again use the derived L'(t) to determine the year when fish is growing at a rate of 6 cm/yr:

                             6 cm/yr = 34.416*e^(-0.18*t)

                             e^(0.18*t) = 34.416 / 6

                             0.18*t = Ln(34.416/6)

                             t = Ln(34.416/6) / 0.18

                             t = 10 year

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3 years ago
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