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pychu [463]
3 years ago
6

HELP WITH THIS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
wlad13 [49]3 years ago
4 0

Answer:

B., E.

Step-by-step explanation:

what was the difficulty ? this is just to understand the movement of a thrown rock.

what happens, when you throw a rock through the air ? it will first move up a little bit, reaches a maximum height, and then drops down again.

that is what the graphic shows.

so, can A. be correct ? no. as we move from 0 seconds to the right (time passes) the height of the rock increases first (before decreasing again later on).

can C. be correct ? no, it would mean that the function would look the same on both sides of the x-axis. this is clearly impossible.

can D. be correct ? no, nowhere in the graph is the height (= the functional value, the y to the x) negative.

can F. be correct ? no, we clearly see the maximum height at 1.5 seconds. at 3 seconds the height is actually at its minimum.

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Find the 16th term to the series PLEASEEE
slavikrds [6]

Answer:

It is a geometric sequence.

common \ ratio , r = \frac{12}{-4}=-3

a_n = a_1 \times r^{n-1} \\n = 16\\r = -3\\a_1 = -4\\a_{16 }= -4 \times (-3)^{15} = -4 \times 14348907 =57395628

5 0
2 years ago
Consider a sphere of radius R > 0. Take two antipodal points A and B on the sphere, and another point C on the sphere. Check
aleksklad [387]

Answer:

To this question; we want to show that if two antipodal points on a sphere were A and B, for any random point C on the sphere, AC is perpendicular to BC?

Step-by-step explanation:

I would proceed by imagining the sphere in a three dimensional Cartesian coordinate system. For example, use a sphere of diameter 2 and let it sit at the origin. Then (0, 0, 1) and (0, 0, -1) are the vector locations of the “north and south poles” of the sphere.

Now choose the vector location of any point on the surface of the sphere. It will have a vector location - we’ll call it (x, y, z). Now the vectors from your point to the two poles are (-x, -y, 1-z) and (-x, -y, -1-z).

Now just form the dot product of those two vectors:

(-x, -y, 1-z) . (-x, -y, -1-z) = x^2 +y^2 + (1-z)*(-1-z)

Now the truth of your claim will be embodied in that dot product being zero:

x^2 + y^2 - (1+z)(1-z) = 0

x^2 + y^2 - (1-z^2) = 0

x^2 + y^2 + z^2 = 1

But that last line is just the definition of points on the surface of a sphere of radius 1, so the claim is proven.

Since R>0 and AC is perpendicular to BC, the <ACB is at right angle.

Please, find attached a simple image to show antipodal points (Two points that makes a diameter) and a point C on the sphere.

5 0
3 years ago
The domain of all step functions is all real numbers<br> true or false
Mariana [72]

Solution:

The domain of all step functions is all real numbers :True

As we know that the domin of a function is defined as the set of values of the variable for which the given function is defined.


Irrespective of the kind of function, domain will be always real numbers.

Hence in our case of step function, the domain will be real numbers only.

Hence the domain of the all the steps functions is all real numbers  only.


3 0
3 years ago
Could anybody help me with this please?
KengaRu [80]
I think the opposite would be a circle because it would have any points.
4 0
2 years ago
Simplify the expression 1.5y2+6.3+6y-3.9-4y+y2​
Lena [83]

Answer: 2.5y^{2} +2y+2.4

Step-by-step explanation:

8 0
3 years ago
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