1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
koban [17]
2 years ago
7

If MO bisects angle PMN, the measure of angle PMN equal 74 and the measure of angle OMN equals 2x + 7, find the value of x

Mathematics
1 answer:
8_murik_8 [283]2 years ago
3 0

Answer:

x = 15

Step-by-step explanation:

Bisects means divide in two equal parts.

Therefore, 74/2 = 37

37 = 2x+7

30 = 2x

15 =  x

x = 15

You might be interested in
Classify the decimal expansion of each fraction as a terminating decimal or a repeating decimal.
Salsk061 [2.6K]

Answer:

repeating-- terminating-- terminating-- repeating.

Step-by-step explanation:

5 0
3 years ago
How do you Simplify 16/12
vlada-n [284]
You need to find a common factor that both the numerator and denominator have. 16 and 12 have common divisible factors of 2 and 4(excluding 1, because 1 is self-defined but doesn't simplify values at all). 

We use the highest factor, in this case, 4. 

Divide 16 by 4 and 12 by 4.

16/4 = 4
12/4 = 3

We put 4 in place of the numerator and 3 in place of the denominator.

\frac{4}{3}
4 0
3 years ago
Read 2 more answers
A chemist examines 12 sedimentary samples for bromide concentraction. The mean bromide concentration for the sample date is 0.43
Umnica [9.8K]

Answer:

a) z = 1.645

b) Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

Step-by-step explanation:

Population is approximately normal, so we can find the normal confidence interval.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645. This is the critical value, the answer for a).

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645*\frac{0.0325}{\sqrt{12}} = 0.015

The lower end of the interval is the sample mean subtracted by M. So it is 0.437 - 0.015 = 0.422cc/m³.

The upper end of the interval is the sample mean added to M. So it is 0.437 + 0.015 = 0.452 cc/m³.

b)

Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

4 0
3 years ago
If b/a=c/b=d/c=2/3, find the value of a:b:c:d
leva [86]

Answer:

the ratio would be 6.75:4.5:3:2

Step-by-step explanation:

replace d and c with

d=2 and c=3

Then using proportion multiplication, you will find that b is 4.5

now replace all b with 4.5.

Then again using proportion multiplication, you will get a is 6.75.

Plug in a, b, c, d in the ratio and you get 6.75:4.5:3:2

5 0
2 years ago
Solve for X and Y
Annette [7]

Answer:

What do you mean?

Step-by-step explanation:

3 0
2 years ago
Other questions:
  • You have a roll of string that is 60 meters long. Which BEST approximates the number of yards of string on the roll? (1 yd = 0.9
    12·2 answers
  • The mass of an object is 12g and its volume is 6cm3. What is its density? *
    9·1 answer
  • A sphere has a radius of 11 feet. A second sphere has a radius of 8 feet. what is the difference of the volume of the spheres
    9·1 answer
  • Write a system of linear equations for (-3, 9) as it’s solution.
    11·1 answer
  • 3x - 6x + 2 &gt; 65<br> Mathematic
    10·2 answers
  • Solve for Theta in the interval...
    5·1 answer
  • 4(1-x)+2x=-3(x+1 solve for x
    7·1 answer
  • Pls help me my grades are not good
    11·1 answer
  • Find the value of each variable. If your answer is not an integer, write it in simplest radical form with the denominator
    13·1 answer
  • zaheeda scored 9 goals in netball matches .At this rate , about how msny goals will she score in ten games​
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!