All categories

3 years ago

Convert .19 into a fraction

Mathematics

2 answers:

STatiana [176]3 years ago

8 0

Here is the decimal:

$0.19 \rightarrow .19$

To convert it into a fraction, make the denominator out of 100, and move the decimal point 2 places to the right and make it the numerator.

$0.19 \rightarrow 19$

Your fraction is:

$\frac{19}{100}$

<h3>CHECK</h3>

To see if the fraction is correct, divide the numerator by the denominator. If you get 0.9, then the fraction is correct.

$19 \div 100 = 0.19$ ✔

Your answer is $\frac{19}{100}$

oee [108]3 years ago

7 0

To write .19 as a fraction, we can multiply both the numerator and denominator to remove the two decimal places.

$\frac{0.19}{1}$ × $\frac{100}{100}$ = $\frac{19}{100}$

Therefore, 0.19 is equivalent to $\frac{19}{100}$ .

You might be interested in

I have one question, i'll give ya'll 50 points!

nika2105 [10]

Answer:

<h3>it's A you're right</h3>

5 0

3 years ago

Which letter accurately describes how w(x) = log4(x + 5) – 3 is translated from p(x) = log4(x).

Irina-Kira [14]

Answer:

B. Left 5 units and down 3 units

5 0

3 years ago

Write an expression to represent the perimeter of:

malfutka [58]

So perimeter is adding all sides

In this picture, you have all sides, so add them up!

(2a-3)+(3a+1)+(2a) = P

So this expression shows that we're adding all sides that gives us the P, or perimeter :)

8 0

3 years ago

Would the hypotenuse of a right triangle with a vertical length of 6 and a horizontal length of 10 have the same slope as the hy

Elodia [21]

No

1. Vertical 6, horizontal 10
6/10 = 3/5 slope

2. (Red) vertical -2, horizontal 3
-2/3 does not equal 3/5

3. (Blue) vertical 4, horizontal 6
4/6 = 2/3 but does not equal 3/5

3 0

3 years ago

The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)

Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics = $\frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } }$ follows $t_n_- _1$ .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores and D = difference between both

So, $\mu_A$ = Population mean for the math scores

$\mu_B$ = Population mean for the writing scores

Let $\mu_D$ = Difference between the population mean for the math scores and the population mean for the writing scores.

<em> Null Hypothesis, </em> $H_0$ <em> : </em> $\mu_A = \mu_B$ <em> or </em> $\mu_D$ <em> = 0 </em>

<em> Alternate Hypothesis, </em> $H_1$ <em> : </em> $\mu_A \neq \mu_B$ <em> or </em> $\mu_D \neq$ <em> 0</em>

Hence, Test Statistics used here will be;

$\frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } }$ follows $t_n_- _1$ where, Dbar = Bbar - Abar

$s_D$ = $\sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}$

n = 12

Student Math scores (A) Writing scores (B) D = B - A

1 540 474 -66

2 432 380 -52

3 528 463 -65

4 574 612 38

5 448 420 -28

6 502 526 24

7 480 430 -50

8 499 459 -40

9 610 615 5

10 572 541 -31

11 390 335 -55

12 593 613 20

Now Dbar = Bbar - Abar = 489 - 514 = -25

Bbar = $\frac{\sum B_i}{n}$ = $\frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}$ = 489

Abar = $\frac{\sum A_i}{n}$ = $\frac{540+432+528+574+448+502+480+499+610+572+390+593}{12}$ = 514

∑ $D_i^{2}$ = 22600 and $s_D$ = $\sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}$ = $\sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} }$ = 37.05

So, Test statistics = $\frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } }$ follows $t_n_- _1$

= $\frac{-25 - 0}{\frac{37.05}{\sqrt{12} } }$ follows $t_1_1$ = -2.34

<em>Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .</em>

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0

3 years ago