I assume that the numbers are supposed to be written as 7.14 x 10^10 for December and 3.21 x 10^10. The total mail delivered is the sum of these two numbers.
(7.14 x 10^10) + (3.21 x 10^10) = 1.035 x 10^11
Let the amount invested with 5% interest be x
Therefore, the amount invested with 6% interest will be (6000-x)
It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:

Multiplying both sides by 100 we get:


Subtracting both sides by 36000 we get:


Thus, the amount invested at 5% is $2250
Therefore, the amount invested at 6% will be $(6000-2250)=$3750
Order the following numbers from greatest to least: 2, -1 , 2.58, -1.65. -1, -1.65, 2, 2.58 2.58, 2, -1.65, -1 2.58, 2, -1 , -1.
saw5 [17]
2.58, 2.58, 2.58, 2.58, 2.58, 2, 2, 2, 2, 2, -1, -1, -1, -1, -1, -1.65, -1.65, -1.65, -1.65, -1.65.
We can see that the line is horizontal so its slope is 0.