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Anika [276]
2 years ago
9

Where are the negative rational numbers placed on a vertical number line?

Mathematics
1 answer:
Y_Kistochka [10]2 years ago
7 0

Answer:

B es pero que te ayude amigo

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X = 4.

You have to distribute by multiplying -4 by the numbers between -3x and -2.

12x + 8 =60

Subtract the 8 from 60 to simplify the equation.

12x = 48

Divide 12 by 48 and get 4.

x=4
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Answer:

Step-by-step explanation:

1. 3x2 + 5x - 4 + 6x2 - x + 7

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= 9x2 + 4x + 3

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= 5y2 - 10y + 1

3. 2x2y - 3xy2 + x2y - 4x2y - 2xy2

= - x2y - 5xy2

4. x2 - y2 + 2x2 - 3xy + 4y2 + 3y2 - 5xy - x2

= 2x2 - 8xy + 6y2

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Cameras R Us has a sale for 25% off camera bags, which is a discount of $20. To find the original cost of the camera bag, Tara c
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6 0
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Find dy/dx by implicit differentiation.
kow [346]

dy/dx by implicit differentiation is cos(πx)/sin(πy)

<h3>How to find dy/dx by implicit differentiation?</h3>

Since we have the equation

(sin(πx) + cos(πy)⁸ = 17, to find dy/dx, we differentiate implicitly.

So, [(sin(πx) + cos(πy)⁸ = 17]

d[(sin(πx) + cos(πy)⁸]/dx = d17/dx

d[(sin(πx) + cos(πy)⁸]/dx = 0

Let sin(πx) + cos(πy) = u

So, du⁸/dx = 0

du⁸/du × du/dx = 0

Since,

  • du⁸/du = 8u⁷ and
  • du/dx = d[sin(πx) + cos(πy)]/dx

= dsin(πx)/dx + dcos(πy)/dx

= dsin(πx)/dx + (dcos(πy)/dy × dy/dx)

= πcos(πx) - πsin(πy) × dy/dx

So, du⁸/dx = 0

du⁸/du × du/dx = 0

8u⁷ × [ πcos(πx) - πsin(πy) × dy/dx] = 0

8[(sin(πx) + cos(πy)]⁷ ×  (πcos(πx) - πsin(πy) × dy/dx) = 0

Since 8[(sin(πx) + cos(πy)]⁷ ≠ 0

(πcos(πx) - πsin(πy) × dy/dx) = 0

πcos(πx) = πsin(πy) × dy/dx

dy/dx = πcos(πx)/πsin(πy)

dy/dx = cos(πx)/sin(πy)

So, dy/dx by implicit differentiation is cos(πx)/sin(πy)

Learn more about implicit differentiation here:

brainly.com/question/25081524

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What exactly are you looking for?

-TTL

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