Question

If g (x) = StartFraction x + 1 Over x minus 2 EndFraction and h(x) = 4 – x, what is the value of (g circle h) (negative 3)?

Answer 1

Answer:

$\frac{8}{5}$

Step-by-step explanation:

Given that $g(x) = \frac{x + 1}{x - 2}$ and h(x) = 4 - x

Now, if y = f(x) and y = g(x) then the composite function (f∘g)(x) is given by f[g(x)].

Hence, (g∘h)(x) = $g[h(x)] = \frac{(4 - x) + 1}{(4 - x) - 2} = \frac{5 - x}{2 - x}$ .......... (1)

Now, from equation (1) we get,

(g∘h)(x) = $\frac{5 - x}{2 - x}$

⇒ (g∘h)(- 3) = $\frac{5 - ( - 3)}{2 - ( - 3)} = \frac{8}{5}$ (Answer)

Answer 2

Answer:

The answer is 8/5

Step-by-step explanation: