How is blood in the pulmanary artery different from blood in other arteries? QUICK ANSWWER
1 answer:
You might be interested in
Check the picture.
since the choices all have rotation about the origin, we must shift the original triangle in a suitable position. This is done by connecting any of the points of A'B'C' to the origin, and extend this line segment, as shown in the picture.
The most appropriate point is C', and we draw C" such that C'O=OC", and C', O and C" are collinear.
We see that the distance CC'' is 5.
So
Answer is:
"<span>A translation 5 units down, followed by a 180-degree counterclockwise rotation about the origin</span>"
since the choices all have rotation about the origin, we must shift the original triangle in a suitable position. This is done by connecting any of the points of A'B'C' to the origin, and extend this line segment, as shown in the picture.
The most appropriate point is C', and we draw C" such that C'O=OC", and C', O and C" are collinear.
We see that the distance CC'' is 5.
So
Answer is:
"<span>A translation 5 units down, followed by a 180-degree counterclockwise rotation about the origin</span>"
9514 1404 393
Answer:
(x, y) = (-1, -16) or (3, 0)
Step-by-step explanation:
Perhaps you want to solve the system of equations ...
- y = x^2 +2x -15
- y -4x = -12
Substituting the first expression for y into the second equation gives ...
x^2 +2x -15 -4x = -12
x^2 -2x -3 = 0 . . . . . . . . add 12
(x -3)(x +1) = 0 . . . . . . . factor
Solutions are the values of x that make the factors zero: x = 3, x = -1.
The corresponding values of y are ...
y = -12 +4x
y = -12 +4{-1, 3} = -12 +{-4, 12} = {-16, 0}
The solutions to the system are ...
(x, y) = (-1, -16) or (3, 0)
