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lilavasa [31]
3 years ago
8

What is the equation of the following? Someone could help me to understand this? thank you​

Mathematics
1 answer:
Troyanec [42]3 years ago
4 0

Answer:

y=(1/5)x

Step-by-step explanation:

First, we must find the slope of the line.

The slope of a line can be found using the formula: (y2-y1)/(x2-x1)

(3-0)/(15-0)

(3)/(15)

1/5

The slope is 1/5.

Next we find the y-intercept, or where the line crosses the y-axis. In this case, the y-intercept is 0.

This gives us the equation: y=(1/5)x

Let me know if this helps!

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Tay–Sachs Disease Tay–Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carri
BARSIC [14]

Answer:

a) 0.0156 = 1.56% probability that all children will develop the disease.

b) 0.4219 = 42.19% probability that only one child will develop the disease.

c) 0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they carry the disease, or they do not. The probability of a children carrying the disease is independent of any other children, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that their offspring will develop the disease is approximately .25.

This means that p = 0.25

Three children:

This means that n = 3

Question a:

This is P(X = 3). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.25)^{3}.(0.75)^{0} = 0.0156

0.0156 = 1.56% probability that all children will develop the disease.

Question b:

This is P(X = 1). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{3,1}.(0.25)^{1}.(0.75)^{2} = 0.4219

0.4219 = 42.19% probability that only one child will develop the disease.

c. The third child will develop Tay–Sachs disease, given that the first two did not.

Third independent of the first two, so just multiply the probabilities.

First two do not develop, each with 0.75 probability.

Third develops, which 0.25 probability. So

p = 0.75*0.75*0.25 = 0.1406

0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

6 0
3 years ago
Middle school basketball court is 74 ft long 42ft wide what is perimeter in feet and meters
MAVERICK [17]
The perimeter in feet is 232 feet and in meters it’s roughly 70 meters
4 0
3 years ago
The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:
Marina CMI [18]
<h2>Answer:</h2>

The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:

                                 Origin.

<h2>Step-by-step explanation:</h2>

A function f(x) is said to be a odd function if:

                    f(-x)=-f(x)

Also, an odd function always has a symmetry with respect to the origin.

whereas a function f(x) is said to be a even function if:

                      f(-x)=f(x)

Also, an even function has a symmetry with respect to the y-axis.

We know that:

Tangent function, cotangent function and cosecant function are odd functions.

Since,

\tan(-x)=-\tan x\\\\\cos (-x)=-\cot x\\\\\csc (-x)=-\csc x

( similarly sine function is also an odd function.

whereas cosine and secant function are even functions )

<em>Hence, the graph of tangent function, cotangent function and cosecant function  is symmetric about the origin.</em>

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Find the value of the following.<br> (a) 180 % of 200g
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Answer:

\frac{180| }{100}  \times 200 = 360

3 0
3 years ago
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Which point satisfies the system of equations y= 3x - 2 and y=-2x + 3?
monitta

Answer:

The points which satisfy the given lines is ( 1 , 1 )  

Step-by-step explanation:

Given as :

The equation of lines is

y = 3 x - 2         ........    1  And

y = - 2 x + 3      ........ 2

From equation given

3 x - 2 = - 2 x + 3

Or , 3 x + 2 x = 3 +2

Or,   5 x = 5

So ,     x = \frac{5}{5} = 1

Put the value of x in eq 1

So, y = 3 ( 1 ) - 2

Or, y = 3 - 2 = 1

∴,  the points ( x , y ) = ( 1 , 1 )

Hence The points which satisfy the given lines is ( 1 , 1 )  Answer

5 0
3 years ago
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