Answer:
Step-by-step explanation:
Arrival rate = ∧ = 2.2 customers per hour
Service rate = u = 5 customers per hour
1. Probability that one customer is receiving a haircut and one customer is waiting
P(2 customers)=(∧/u)^2 * (1-∧/u)=(2.2/5)^2 * (1-2.2/5)=0.1936*0.56= 0.108416
2. Probability that one customer is receiving a haircut and two customers are waiting
P(3 customers)= (∧/u)^3 * (1-∧/u)=(2.2/5)^3 * (1-2.2/5)= 0.085184
* 0.56= 0.04770304
3. Probability that more than two customers are waiting
P(more than 3 customers)=1- P(less than 3 customers) =
1- [P(0)+P(1)+P(2)+P(3)]=
= 1- [(1-2.2/5) +2.2/5*(1- 2.2/5) + 0.108416+0.04770304]=1-0.9625=0.0375
3. Probability that more than two customers are waiting =
Answer:
1 1/5
Step-by-step explanation:
Put y in the x+2y-6. x+2(3x-7)=0. So x+6x-14=0. 7x-14=0. 7x=14. x=2
Answer:
You should stock 59 thousands of postcards
Step-by-step explanation:
In the standard normal distribution table, you want to find the Z with probability 0.4, which is (see figure attached) 1.28. Z is calculated as follows:
Z = (x - μ)/σ
where μ is the mean and σ is the standard deviation. Replacing with data:
1.28 = (x - 50)/7
x = 1.28*7 + 50 = 59 thousands of postcards
So, approximately 80% of the demand would be satisfied with a number of postcards between 41000 and 59000 (notice the curve is symmetrical).
