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masya89 [10]
2 years ago
10

A jewelry store is featuring a diamond in the shape of a square pyramid. The side length of

Mathematics
1 answer:
BARSIC [14]2 years ago
7 0

Answer:

128√5/3 mm³

Step-by-step explanation:

Since we are not told what to find, we can as well look for the volume of the pyramid

Volume of a square pyramid: V = (1/3)a²h

a is the side length of the square

h is the height of the pyramid

Given

a = 8mm

l² = (a/2)² + h²

l² = (a/2)² + h²

6² = (8/2)² + h²

h² = 6² - 4²

h² = 36 - 16

h² = 20

h = √20

Volume of a square pyramid =  (1/3)*8²*√20

Volume of a square pyramid = 1/3 * 64 * 2√5

Volume of a square pyramid = 128√5/3 mm³

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There are three possible outcomes that you may encounter when working with these system of equations:


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  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
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We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

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5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

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6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



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