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Vika [28.1K]
3 years ago
10

Write an equation of a line that is parallel to y=-3x+5 that passes through the point (0,-4)

Mathematics
1 answer:
elena55 [62]3 years ago
6 0

Answer:

{ \rm{y =  - 3x + 5}}

Gradient = -3

• Parallel lines have the same gradient, therefore gradient, m is -3

{ \rm{y = mx + c}}

• At point (0, -4)

{ \rm{ - 4 = ( - 3 \times 0) + c}} \\  \\ { \rm{c =  - 4}}

y intercept is -4

{ \boxed{ \boxed{ \mathfrak{answer : }}{ \rm{\:  \: y =  - 3x - 4}}}}

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Plssss help quick i need it for sum important
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(a) The product of (2x-4)\ and\ (3x^2-x+4)  is calculated to be =6x^3-14x^2+12x-16

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<u>(a)</u>

(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16

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