So for this question, we're asked to find the quadrant in which the angle of data lies and were given to conditions were given. Sign of data is less than zero, and we're given that tangent of data is also less than zero. Now I have an acronym to remember which Trig functions air positive in each quadrant. . And in the first quadrant we have that all the trig functions are positive. In the second quadrant, we have that sign and co seeking are positive. And the third quadrant we have tangent and co tangent are positive. And in the final quadrant, Fourth Quadrant we have co sign and seeking are positive. So our first condition says the sign of data is less than zero. Of course, that means it's negative, so it cannot be quadrant one or quadrant two. It can't be those because here in Quadrant one, we have that all the trick functions air positive and the second quadrant we have that sign. If data is a positive, so we're between Squadron three and quadrant four now. The second condition says the tangent of data is also less than zero now in Quadrant three. We have that tangent of data is positive, so it cannot be quadrant three, so our r final answer is quadrant four, where co sign and seek in are positive.
As you see in the picture, there are two lines that could maybe represent two linear functions. However, this is not true because of the solid point and the hollow point. This is an inequality equation that has points of discontinuity.
Points of discontinuity are breaks in the graph that are a result of an undefined point when the f(x) is substituted with a point of x that is not part of the solution. So, technically, the graph is made from one rational expression.
So, when it says f(-2), this is the y-value at x=-2. That means f(-2)=2, f(0)=3 and f(4)=-1. Specifically, there are two points at x=0, but we take the solid point only.
Answer: The ΔVZX and ΔWXZ are not congruent by SAS.
Explanation:
It is given that the VX = WZ = 40 cm and ∠ZVX = ∠XWZ = 22°.
Draw a figure as shown below,
According to the SAS rule of congruence, two triangles are congruent if two sides and their inclined angle is equal.
From the given figure it is easily noticed that in ΔVZX and ΔWXZ,
(given)
(given)
(common side)
Since we have two sides and one angle is same. but we can not conclude that the ΔVZX and ΔWXZ are congruent by SAS, because the given angle is not the inclined angle of both equal sides.
Therefore, the ΔVZX and ΔWXZ are not congruent by SAS.
It might be 31 if you add all the numbers together but I'm not positive.
