You take the derivative of the position equation s(t) = -3 + 4

and you get v(t) = 8t
now plug in 5
v(5) = 40
40 m/s
is your answer
what is the equation in point slope form of the line passing through (-2,-5) and (2,3)
Point slope form: y - y1 = m(x - x1)
m = (3 + 5)/(2 + 2) = 8/4 = 2
Point slope form:
y - 3 = 2(x - 2) if you're using this (2,3)
or
y + 5 = 2(x + 2) if you're using this (-2,-5)
Answer:
→ 1 hour : 16/21 dresses
Step-by-step explanation:
you can simplify if you want!
The curve

is parameterized by

so in the line integral, we have





You are mistaken in thinking that the gradient theorem applies here. Recall that for a scalar function

, we have gradient

. The theorem itself then says that the line integral of

along a curve

parameterized by

, where

, is given by

Specifically, in order for this theorem to even be considered in the first place, we would need to be integrating with respect to a vector field.
But this isn't the case: we're integrating

, a scalar function.
The answer is B. 5.6 kilometers. 5.592 miles are in 9 kilometers which would round up to 5.6