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Rudiy27
2 years ago
13

Write the equation of the line described below in slope-intercept form.

Mathematics
1 answer:
choli [55]2 years ago
8 0

\huge\boxed{\mathcal{HELLO!:)}}

\star\bigstar\star Parallel lines have the same slope. Remember, parallel lines never intersect. Lines with the same slope, but different y-intercepts will not intersect.

\star\bigstar\starNow, we have the slope of the line and a point that it passes through.

We can use the Point-Slope Formula:

\huge\boxed{\bf{y-y1=m(x-x1)}}

Remember, y1 is the y-coordinate of the point, m is the slope, and x1 is the x-coordinate.

Plug in the values:

y-(-8)=1(x-(-10)

y+8=1(x+10)

y+8=x+10

y=x+10-8

y=x+2

\huge\boxed{\mathbb{ANSWER:{\boxed{\bf{y=x+2}}}}}

\star\bigstar\star I hope it helps you!

\bold{Have~a~great~day!}

\rm{FabulousKingdom:-)

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Two gears are connected and are rotating simultaneously. The smaller gear has a radius of 3 inches, and the larger gear has a ra
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Circumference of a circle is C = 2πr.

part 1)

so the radius of the smaller gear is 3 inches, so after a full rotation, namely a revolution, the smaller gear has covered an arc of 2π(3), or 6π.

what angle has the larger gear of 7 inches in radius, has it covered with an arc of 6π?

\bf \textit{arc's length}\\\\
s=r\theta ~~
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad radians\\
------\\
s=6\pi \\
r=7
\end{cases}\implies 6\pi =7\theta \implies \cfrac{6\pi }{7}=\theta



part 2)

since the larger gear has a radius of 7, in a revolution it will have an arc of 2π(7), or 14π.

now, we know the smaller gear does a 6π arc in a revolution, how many revolutions will it do in an arc of 14π?

\bf \begin{array}{ccll}
arc&revolution\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
6\pi &1\\
14\pi &x
\end{array}\implies \cfrac{6\pi }{14\pi }=\cfrac{1}{x}\implies \cfrac{3}{7}=\cfrac{1}{x}\implies x=\cfrac{7}{3}
6 0
3 years ago
PLEASE HELP ME I DON T UNDERSTAND IF YOU PLEASE COULD HELP ME I WOULD GREATLY APPRECIATE IT REALLY THANK YOU
butalik [34]

Find the length of one side.

V = s^3

s = cube root of V

V = 729

s = cube root 729

s = 9

Put this into your calculator as 729^0.333333333

It should bring back 9 or 8.999999 something which means 9.

Net

The net is shown below. You will have to do the labeling. But I can tell you what you should label each face as?

Area of one face = s^2

s = 9

Area of one face = 9*9

Area of one face = 81

So when you draw this, each face should be labeled with 81.

It should have it's units (ft^2) if your marker is picky.

Part C

There are 6 sides.

1 side has an area of 81 ft^2

6 sides have an area of 6*81 = 486 ft^2

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Answer:

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Step-by-step explanation:

The equation says y equals 5. I attached a graph below:

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