Answer:
Security technician
Explanation:
Security technicians are responsible for fixing, planning, and implementing the IT and computer security system of organisations by making sure the safety and security of the data and information of the clients as well as the employees that make daily use of the systems
Security technicians administer security access to the clients and employees of the organization and are responsible for being up to date with the latest IT security technology developments.
Answer:
The benefits of SSDs over HDDs include:
Faster read/write speeds. SSDs can access large files quickly.
Quicker boot times and better performance. Because the drive does not need to spin up as an HDD would, it is more responsive and provides better load performance.
Durability. ...
Power consumption. ...
Quieter. ...
Size.
Explanation:
Over a TCP connection, suppose host A sends two segments to host B, host B sends an acknowledgement for each segment, the first acknowledgement is lost, but the second acknowledgement arrives before the timer for the first segment expires is True.
True
<u>Explanation:</u>
In network packet loss is considered as connectivity loss. In this scenario host A send two segment to host B and acknowledgement from host B Is awaiting at host A.
Since first acknowledgement is lost it is marked as packet lost. Since in network packet waiting for acknowledgement is keep continues process and waiting or trying to accept acknowledgement for certain period of time, once period limits cross then it is declared as packet loss.
Meanwhile second comes acknowledged is success. For end user assumes second segments comes first before first segment. But any how first segment expires.
Answer:
Replace /* Your solution goes here */ with the following expression
accelGravity = (G * M) / (distCenter *distCenter );
Explanation:
Required
Complete the code
The equivalent expression of (G * M) / (d^2) is:
(G * M) / (distCenter *distCenter );
The expression must be stored in accelGravity.
So, we have:
accelGravity = (G * M) / (distCenter *distCenter );
