Answer:
The Taylor series of f(x) around the point a, can be written as:
Here we have:
f(x) = 4*cos(x)
a = 7*pi
then, let's calculate each part:
f(a) = 4*cos(7*pi) = -4
df/dx = -4*sin(x)
(df/dx)(a) = -4*sin(7*pi) = 0
(d^2f)/(dx^2) = -4*cos(x)
(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4
Here we already can see two things:
the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.
so we only will work with the even powers of the series:
f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....
So we can write it as:
f(x) = ∑fₙ
Such that the n-th term can written as:
Answer:
Step-by-step explanation:
<u><em>x-intercept</em></u>
<u><em>y-intercept </em></u>
Answer:
Option B is correct
Step-by-step explanation:
Given that:
and 
are supplementary.
prove that: 
It is given that:
and are supplementary.
By definition of supplementary
⇒
.....[1]
From the figure, you can see that:
and 
are also supplementary.
⇒
.....[2]
By [1] and [2] we have;
⇒
Simplify:
Since ∠2 and ∠3 are corresponding angles.
Corresponding angles states when the two lines are parallel, then Corresponding Angles are equal and vice versa.
by definition we have;
proved!
The answers are as follows:
Box 1) D
Box 2) .02D
Box 3) D + .02D
Answer:
your finding the absolute value, I I this means absolute value which means if its negative it automatically is its own number you get rid of the negative sign if it's positive just keep it because it's already in it's normal number.
For example: I -4 I = 4
For example: I -5 I = 5
For example: I 3/4 I = 3/4
For example: I 3 I = 3
For example: I 4 I = 4
