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zhuklara [117]
3 years ago
9

En Drosophila existe una mutación llamada Curly (Cy) que da lugar a que el ala se curve hacia arriba. Cuando se cruza un macho C

y con una hembra virgen Cy, la F1 está formada por 207 moscas Cy y 101 moscas normales. ¿Puede proponer una hipótesis para explicar estos resultados?
Biology
1 answer:
andre [41]3 years ago
5 0

Answer:

Cy es un alelo letal en homocigosis

Explanation:

Alelos:  

Cy: alas curvadas y N: alas normales

Cruzamiento: CyN (macho) x CyN (hembra)

F1: 207 Cy + 101 normales (2/3 alas curvadas y 1/3 alas normales)

Cuando se cruzan 2 ejemplares heterocigotas para un gen con dominancia incompleta, la proporción fenotípica que uno espera en la progenie será 1:2:1 (1 homocigota dominante, 2 heterocigotas y 1 homocigota recesivo). En este caso solamente se observan dos fenotipos: moscas con alas normales y moscas con alas curvadas (Cy), con una proporción fenotípica de 1:2. En consecuencia, si Cy es un gen letal en homocigosis, la proporción fenotípica será 2/3 CyN y 1/3 NN, lo cual se ajusta a una proporción fenotípica de 1:2 y a los valores esperados en la prueba de chi cuadrado χ² obtenidos usando los datos del experimento, es decir, 207 moscas Cy y 101 moscas normales:

Observados       Esperados

207                     308 x 2/3 = 205,3

101                       308 x 1/3 = 102,7

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