The electric field in an xy plane produced by a positively charged particle is 8.55(4.5 3.0 ) N/C at the point (4.2, 4.9) cm and
126 N/C at the point (2.2, 0) cm. What are the (a) x and (b) y coordinates of the particle
1 answer:
Answer:
(a) x=-3.15cm
(b)y=0cm
Step-by-step explanation:
Locate the point (4.2,4.9) cm and draw the vector 4.5i+3.j with the origin at this point, the end of the vector is going to be in the point (8.7,7.9). With point (2.2,0), after searching, draw a line to the right to represent that the direction of the field is toward the positive x-axis.
Draw a line in each point in the opposite direction of the field in that point, the point where these lines intersect each other is the position of the particle.
Is the point (-3.15,0)cm
(a) x=-3.15cm
(b)y=0cm
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Answer:
(-∞, -2), (-2, -0.618), and (1.618, 3)
Step-by-step explanation:
The red arrows indicate the regions in which the function is decreasing.
The corresponding intervals are (-∞, -0.618) and (1.618, 3),
Let's examine the intervals given.
(-∞, -2): Yes, decreasing.
(-2, -0.618): Yes, decreasing.
(-2, 0.689): No. Decreasing in (-2, -0.618) but increasing in (-0.618, 0.689).
(-1.17, 0.689): No. Decreasing in (-1.17, -0.618) but increasing
in (-0.618, 0.689).
(0.698, 71.457): No. Increasing from (0.698, 1.618), decreasing in (1.618, 3) and increasing in (3, 71.457).
(1.618, 3): Yes, decreasing.
(2.481, ∞): No. Decreasing in (2.481, 3) but increasing in (3, ∞).
The three choices that indicate a decreasing interval are (-∞, -2),
(-2, -0.618), and (1.618, 3).
