Solve for x A) 8 B) 10 C) -11 D) 5
2 answers:
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Answer:
We conclude that this is an unusually high number of faulty modems.
Step-by-step explanation:
We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.
The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.
Let p = <em><u>population proportion</u></em>.
So, Null Hypothesis, : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}
Alternate Hypothesis, : p > 0.013 {means that this is an unusually high number of faulty modems}
The test statistics that would be used here <u>One-sample z-test</u> for proportions;
T.S. = ~ N(0,1)
where, = sample proportion faulty modems=
= 0.027
n = sample of modems = 367
So, <u><em>the test statistics</em></u> =
= 2.367
The value of z-test statistics is 2.367.
Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>
Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.
Therefore, we conclude that this is an unusually high number of faulty modems.
Answer:
The rate at which the population decrease is 59.8 %
Step-by-step explanation:
Given as :
The population of city = 30,31,000
Now The population of city decrease to 22,46,000
The time period in which population decrease is 50 years
Let the percentage rate of decrease = R%
So,
Final population = initial population ×
Or, 22,46,000 = 30,31,000 ×
Or, =
Or, =
=
So , 0.99402 =
Or, = 1 - 0.99402
So, Rate = × 100
Or, Rate = 0.598 = 59.8 %
Hence The rate at which the population decrease is 59.8 % Answer