Answer:
10,346.0(1.1)^x
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Step-by-step explanation:
edg
Would it be (5,3) reflected?
The roots: this is when y=0, so in yours there are 2 roots. Just look at the x value when y=0 and that is your roots.
Y intercept- this is when x=0, so just look at the y value below x=0 and that is the y intercept. Note the answer will probably be in the form (0,_)
Vertex=do you see a pattern? Well the vertest would be the highest or lowest point of the quadratic equation. Your vertex would be (5,-9) because just look at x=4 and x=6, bit of the y values are -8 and when you look at x=3 and x=7 they are also the same because this is a quadratic equation.
Max or min: yours is a minimum because (5,-9) is the lowest point. Every value left and right of this are higher up the graph, so this would be a minimum.
*something that will help you see this all more clearly is if you graphed this or put it into Desmos to see the vertex etc.
Answer:<em><u>Lcm</u></em><em><u> </u></em><em><u>we</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>get</u></em><em><u>:</u></em><em><u> </u></em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>2</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>2</em><em> </em><em> </em><em>3</em><em> </em><em> </em><em>4</em><em> </em><em> </em><em>2</em><em> </em><em> </em><em>5</em><em> </em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>3</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>1.</em><em> </em><em>3.</em><em> </em><em>2.</em><em> </em><em>1.</em><em> </em><em>5</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>5.</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>1</em><em> </em><em> </em><em>1</em><em> </em><em> </em><em>2.</em><em> </em><em> </em><em>1</em><em> </em><em> </em><em> </em><em>5</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>2.</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>1.</em><em> </em><em>1.</em><em> </em><em> </em><em>1.</em><em> </em><em>1.</em><em> </em><em> </em><em> </em><em>1</em>
<em>LCM</em><em>=</em><em>15</em><em>×</em><em>4</em><em>=</em><em>6</em><em>0</em>
First, we have to figure out the angles on the interior of the triangles. Since the 90° angle and the angle next to it form a straight line, we know that they are supplementary and add up to 180°. We would then subtract 90° from 180° to find the value of that angle, which comes out to be 90°. Next, since the angle measuring 125° and the angle next to it are supplementary, we would repeat the same procedure: 180° - 125° = 55°. Now that we know the values of two of the interior angles of the triangle, we can solve for the third. The angles of a triangle should add up to 180°, so we can solve for <em>p</em> like this:
90 + 55 + <em>p</em> = 180
145 + <em>p</em> = 180
<em>p </em>= 180 - 145
<em>p</em> = 35
The value of <em>p</em> <em />is 35°.