Based on the right angle triangle and the given parameters, cos K = 5/13
<h3>Trigonometric ratios</h3>
- sin = opposite / hypotenuse
- cos = adjacent / hypotenuse
- Tan = opposite / adjacent
Given parameters:
- Hypotenuse = 13
- Adjacent = 5
- Opposite = 12
Therefore,
cos K = adjacent / hypotenuse
cos K = 5/13
Learn more about right triangle:
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so, as you can see above, the common ratio r = 1/2, now, what term is +4 anyway?
so is the 8th term, then, let's find the Sum of the first 8 terms.
![\bf S_8=512\left[ \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right]\implies S_8=512\left(\cfrac{1-\frac{1}{256}}{\frac{1}{2}} \right)\implies S_8=512\left(\cfrac{\frac{255}{256}}{\frac{1}{2}} \right)\\\\\\S_8=512\cdot \cfrac{255}{128}\implies S_8=1020](https://tex.z-dn.net/?f=%20%5Cbf%20S_8%3D512%5Cleft%5B%20%5Ccfrac%7B1-%5Cleft%28%20%5Cfrac%7B1%7D%7B2%7D%20%5Cright%29%5E8%7D%7B1-%5Cfrac%7B1%7D%7B2%7D%7D%20%5Cright%5D%5Cimplies%20S_8%3D512%5Cleft%28%5Ccfrac%7B1-%5Cfrac%7B1%7D%7B256%7D%7D%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%20%5Cright%29%5Cimplies%20S_8%3D512%5Cleft%28%5Ccfrac%7B%5Cfrac%7B255%7D%7B256%7D%7D%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%20%5Cright%29%5C%5C%5C%5C%5C%5CS_8%3D512%5Ccdot%20%5Ccfrac%7B255%7D%7B128%7D%5Cimplies%20S_8%3D1020%20)
1 = 32
2 = 148
3 = 32
4 = 148
5 = 32
6 = 148
7 = 32
8 = 148
Yes, 5:4 is the simplified form of 25:16. 25 divided by 5 is 5 (the lowest possible number it can be made into). 16 divided by 4 is 4 (also the lowest possible number it can be made into).
Number one would be no solution
