We can factor by grouping. To do so, we multiply the leading coefficient with the constant at the end. In other words, a times c (ax^2 + bx + c).
15*-4 = -60
Now we need to split the b term into two pieces that multiply to -60 and add to 4.
-6 and 10 will work.
Now group one part of b with the 15x^2 and the other part with -4.
(15x^2 + 10x) + (-6x - 4)
Now factor both terms.
5x(3x+2) - 2(3x+2)
3x+2 is one of our factors and 5x-2 is the other.
(3x+2)(5x-2)=0
Now just find the zeros.
3x+2 = 0
3x = -2
x = -2/3
And
5x-2 = 0
5x = 2
x = 2/5
So the answer is x = -2/3 and x = 2/5
<u>Answer:</u>
$50 and $115
<u>Step-by-step explanation:</u>
We know that,
the sum of the two rates = $165 per hour
Let x and (165 - x) represent the $/hour of the 15hr and 5hr mechanics respectively.
Then combining their charges together to get:

Solving for x to get:



So the rate charged per hour by one mechanic is $50 and for the other mechanic =
$115.
Answer:
answer of this question is
35.24
Answer:
x = 5
Step-by-step explanation:
Maybe you have ...
n(x) = 2x +7
and you want x for n(x) = 17.
17 = 2x +7
10 = 2x . . . . . . subtract 7
5 = x . . . . . . . . divide by 2