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2 years ago

15

which population will be larger after 30 years: population x that doubles it's self every year, or population y that increases b

y a million people every year?

1 answer:

Lisa [10]2 years ago

6 0

Population y that increases by a million people every year

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Anybody wanna bless me with $1-$5 on cashapp??? I’m down bad right now ... ($annaly99)

amm1812

Answer:

Step-by-step explanation:

I dont have cashapp sorry

8 0

2 years ago

A multiple-choice test consists of 10 questions. Each question has answer choices of a ,b c, d ,e , and , and only one of the ch

aalyn [17]

Its easier to find the complement of that instead
so you find the probability of 1 and 0
The .2 in the answer is the probability of each question 1/5
(10 C 0) x .2^0 (1-.2)^10-0=.1074
(10 C 1) x .2^1 (1-.2)^10-1=.2684
.2684+.1074=.3758 and that's the complement
so 1 - .3758= .6242
I too have a stats exam on this tomorrow lol

4 0

2 years ago

The owner of an auto repair shop studied the waiting times for customers who arrive at the shop for an oil change. The following

labwork [276]

Answer:

(d)0.6

Step-by-step explanation:

(a)Frequency Distribution

$\left|\begin{array}{c|c}$Waiting Time(in Minutes)&$Frequency\\-----------&--\\0-4&4\\5-9&8\\10-14&5\\15-19&2\\20-24&1\\--&--\\Total&20\end{array}\right|$

(b)The relative frequency distribution.

$\left|\begin{array}{c|c}$Waiting Time(in Minutes)&$Relative Frequency\\-----------&--\\0-4&4/20=0.2\\5-9&8/20=0.4\\10-14&5/20=0.25\\15-19&2/20=0.1\\20-24&1/20=0.05\\--&--\\Total&1\end{array}\right|$

(c)The cumulative frequency distribution.

$\left|\begin{array}{c|c|c}$Waiting Time(in Minutes)&$Frequency&$Cumulative Frequency\\-----------&--&---\\0-4&4&4\\5-9&8&12\\10-14&5&17\\15-19&2&19\\20-24&1&20\\--&--&--\\Total&20\end{array}\right|$

(d)The proportion of customers needing an oil change who wait 9 minutes or less.

Proportion of customers needing an oil change who wait 9 minutes or less.

$=\dfrac{12}{20} \\\\=0.6$

5 0

3 years ago

Write an expression that is equivalent to (3b+6) + 2

cluponka [151]

Since you're not multiplying, you can remove the parentheses.

3b+6+2

which gives you . ....

3b+8

3 0

3 years ago

Read 2 more answers

Please help: linear algebra problem. (Linear combinations)

DochEvi [55]

Answer:

$\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

This tells us that:

$A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]$

$b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

$c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$ .

So we want to find a way to express this as:

Ax=b where x is the scalar vector, $\left[\begin{array}{ccc}c\\d\end{array}\right]$ .

So we can write this as:

$\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

3 0

2 years ago