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arsen [322]
3 years ago
6

I need help please please.

Mathematics
2 answers:
Hitman42 [59]3 years ago
7 0

Answer:

C

15(2/3)=10

15/1 x 2/3 = 10

30/3=10

10=10

Step-by-step explanation:

Artyom0805 [142]3 years ago
4 0

Answer:

C apparently from what the guy above me said

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Jacob now has 600 dollars.
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4 groups of 5 hundredths
natka813 [3]

twenty hundretdths is what I assume the answer is


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3 years ago
Two numbers are in the ratio 5:2 and their sum is 56. Find the numbers. Please plain how to do this
hoa [83]

Answer:

40 and 16

Step-by-step explanation:

Let's say these numbers are 5x and 2x.

Their sum is 56, so

5x + 2x = 56

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Now substitute the unknown value with 8.

5 · 8 = <u>40</u>,

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5 0
3 years ago
How do I solve -3x=x-(6-2x)?
nydimaria [60]

Answer:

X is 1.

Step-by-step explanation:

-3x = x - ( 6 - 2x )          Distribute the negative sign

-3x = x - 6 +2x               Combine like terms

-3x = 3x -6                     Subtract 3x on both sides

-6x = -6                          Isolate the variable by dividing -6 on both sides

x    =  1

<h3><u><em>Hope this helps!!!</em></u></h3><h3><u><em>Please mark this as brainliest!!!</em></u></h3><h3><u><em>:)</em></u></h3>
8 0
3 years ago
I need help I’m struggling
andrew-mc [135]
All you need for a point to be left unchanged is it being on the line of reflection. (Generally speaking)

The first one is wrong cause you can have a line of reflection anywhere. If the line is horizontal ( x axis) then the slope would be zero. Whereas a line on y axis would be an undefined slope. There are also diagonal lines of reflections which have slopes

I am pretty sure the second one would be correct because, as previously stated, all the line needs to stay in the same place is it being on the line of reflection.

Again, lines of reflection do not have a set slope, a diagonal line of reflection going like / on the chart through the axis could have a slope of one, but it is not needed for the point to remain in the same place

The point does not necessarily need to be on the origin, it can be anywhere on the line of reflection, and if the line of reflection does not pass through the origin, a point on the origin would be moved in a reflection.

I hope this makes sense and helps you out a bit... have a good day
8 0
3 years ago
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