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horrorfan [7]
3 years ago
12

Part A: Write an algebraic expression for 8 more than 5 times a number. (5 points)

Mathematics
1 answer:
Harman [31]3 years ago
4 0
Part A: 5x + 8

Part B: The sum of 6 and a number, increased 4 times.
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Suppose the average yearly salary of an individual whose final degree is a​ master's is ​$46 thousand less than twice that of an
seraphim [82]

Answer:

The average sallary of a Master's is 60 thousand and of a Bachellor's is 53 thousand.

Step-by-step explanation:

In order to solve this problem we first need to attribute variables to the unkown quantities. We will call the average salary of Master's "x" and the average salary of a Bachellor's "y". The first information the problem gives us is:

x = 2*y - 46

The second one is:

x + y = 113

We now have two equations and two variables, so we can solve the system. To do that we will use the value for x from the first equation on the second one. We have:

2*y - 46 + y = 113

3*y = 113 + 46

3*y = 159

y = 159/3 = 53

x = 2*(53) - 46 = 60

The average sallary of a Master's is 60 thousand and of a Bachellor's is 53 thousand.

3 0
3 years ago
Patrick is replacing a door in his house. It has a height of 80 inches and its diagonal is 89 inches. What is the width of the d
Sedbober [7]
72 I think I hope its right I had to write all over my paper lol
6 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by
a_sh-v [17]

Answer:

Dimension of the box is 16.1\times 7.1\times 2.45

The volume of the box is 280.05 in³.

Step-by-step explanation:          

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is L=21-2h

The width of the box is W=12-2h

The volume of the box is V=L\times W\times H

V=(21-2h)\times (12-2h)\times h

V=(21-2h)\times (12h-2h^2)

V=252h-42h^2-24h^2+4h^3

V=4h^3-66h^2+252h

To maximize the volume we find derivative of volume and put it to zero.

V'=12h^2-132h+252

0=12h^2-132h+252

Solving by quadratic formula,

h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}

h=\frac{132\pm72.99}{24}

h=2.45,8.54

Now, substitute the value of h in the volume,

V=4h^3-66h^2+252h

When, h=2.45

V=4(2.45)^3-66(2.45)^2+252(2.45)

V\approx 280.05

When, h=8.54

V=4(8.54)^3-66(8.54)^2+252(8.54)

V\approx -170.06

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is L=21-2(2.45)=16.1

The width of the box is W=12-2(2.45)=7.1

So, Dimension of the box is 16.1\times 7.1\times 2.45

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3 years ago
Please help me with this problem, and can you also show steps. thank you
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