Answer:
1st one
Step-by-step explanation:
R is 4 if I'm wrong sorry
The value of x from the given triangle is 32√3/3
<h3>SOH CAH TOA identity</h3>
In order to determine the value of x, first we need to determine the hypotenuse side of the smaller triangle.
sin 60 = 8√2/H
H = 8√2/sin60
H = 8√2 * 2/√3
H = 16√2/√3
H = 16√6/3
For the value of x, we will use the expression
sin45 = (16√6/3)/x
1/√2 = 16√6/3x
3x = 16√12
3x = 32√3
x = 32√3/3
Hence the value of x from the given triangle is 32√3/3
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Input Data :
Point 1 ( x A , y A ) = (-6, -2)
Point 2 ( x B , y B ) = (1, -6)
Objective :
Find the distance between two given points on a line.
Formula :
Distance between two points = √ ( x B − x A )2 + ( y B − y A ) 2
Solution :
Distance between two points = √ ( 1 - -6 ) 2 + ( − 6 − − 2 ) 2
= √ 7 2 + ( − 4 ) 2
= √ 49 + 16
= √ 65 = 8.0623
Distance between points (-6, -2) and (1, -6) is 8.0623
Or 8.
Best of luck!!
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