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3 years ago

What is the product? 5k/6 x 3/2k^3

Mathematics

1 answer:

mr_godi [17]3 years ago

3 0

Answer:

5/4k^2

Step by step explanation

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What is the probability that a randomly chosen male voter is a registered democratic? Round your answer to the nearest tenth of

sasho [114]

Answer:

600/2222. simplify it

Step-by-step explanation:

4 0

3 years ago

Find the area of a circle that has a diameter of 11 inches. Approximate Π as 3.14. Round your answer to the nearest hundredth.

Alexus [3.1K]

Answer: 94.99 in^2

Step-by-step explanation: The equation for the area of a circle is A=πr^2. To solve this, we need to find the radius. The diameter is the whole circle, whole the radius is half. So divide the diameter by 2.

11/2 = 5.5

The radius is 5.5 inches. Plug the radius into the equation.

A=π5.5^2

Square the 5.5 first. You will get 30.25.

A=π30.25

Plug in 3.14 for pi.

A=3.14 x 30.25

Multiply.

A=94.985

Round to the nearest hundredth.

A=94.99

The area of the circle is 94.99 in^2.

7 0

4 years ago

How to solve I don't know how to go about it

Tems11 [23]

Mathpapa on google ok

7 0

3 years ago

Point m is the midpoint of ab¯¯¯¯¯ . am=2x+9, and ab=8x−50. what is the length of am¯¯¯¯¯¯ ?

iogann1982 [59]

Since m is the midpoint of ab, then the following relationship is fulfilled:
$am = \frac{ab}{2}$
Therefore, substituting values we have:
$2x+9 = \frac{8x-50}{2}$
From here, we clear the value of x.
We have then:
$2x+9 = 4x-25$
$9+25 = 4x-2x$
$34 = 2x$
$x = \frac{34}{2}$
$x = 17$
Then, the value of am, is given by substituting x in the expression:
$am=2x+9$
Substituting we have:
$am=2(17)+9$
$am=34+9$
$am=43$
Answer:
the length of am is:
$am=43$

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4 years ago

Define mean deviation and standard deviation.

Alina [70]

Answer:

The standard deviation is simply the square root of the variance. The average deviation, also called the mean absolute deviation, is another measure of variability. To calculate the average deviation, simply subtract the mean from each value, then sum and average the absolute values of the differences.

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4 years ago