Question

B(n)=−4−2(n−1)b, left parenthesis, n, right parenthesis, equals, minus, 4, minus, 2, left parenthesis, n, minus, 1, right parenthesis
Find the 12^\text{th}12


th


12, start superscript, start text, t, h, end text, end superscript term in the sequence.

Answer 1

Answer:

12th term would be -26.

Step-by-step explanation:

Given explicit formula of a sequence,

$b(n) = -4 - 2(n-1)$

Where,

n = number of a term.

i.e. 12th term will get after putting n = 12 in the formula.

Hence, 12th term of the sequence would be,

$b(12) = -4 - 2(12-1)$

$=-4-2(11)$

$= -4 - 22$

$= -26$