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Irina18 [472]
3 years ago
7

One of the roots of the quadratic equation x^2−5mx+6m^2=0 is 36. Find the greatest possible value of the second root. 100PTS!!!

Mathematics
2 answers:
rosijanka [135]3 years ago
7 0

Answer:

The greatest possible value is 54

Step-by-step explanation:

Solve the quadratic equation

Given

x² - 5mx + 6m² = 0

We can rewrite this as

x² - 3mx - 2mx + 6m² = 0

(x² - 3mx) - (2mx - 6m²) = 0

x(x - 3m) - 2m(x - 3m) = 0

(x - 2m)(x - 3m) = 0

x - 2m = 0 or x - 3m = 0

So,

x = 2m or x = 3m .

2m and 3m are the roots of the equation.

Since one of the roots is 36

Assume

2m = 36

m = 36/2 = 18

3m is

3(18) = 54

If 3m = 36

m = 12

And

2m = 2(12) = 24.

The greatest possible value is 54

Maru [420]3 years ago
6 0

Answer:

54

Step-by-step explanation:

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weeeeeb [17]
At the end of 1st year it depreciates by 15%, so it reduces by 100% - 15% = 85%

At the end of 2nd year it depreciates by 15% again, so it reduces by 100% - 15% = 85%

At the end of 3rd year it depreciates by 15% again, so it reduces by 100% - 15% = 85%

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Answer:

g < 10

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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