3 years ago

A chord PQ of length 13cm is drawn in a circle with center C and a radius of 10.2cm.

Mathematics

1 answer:

Reika [66]3 years ago

3 0

Cududjdjdjdkdkdkdkfkiddi

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3 years ago

Expand and simplfy (2x+1)(x+3)

Nina [5.8K]

Answer:

(2x+1)(x+3)

2x(x+3)+1(x+3)

2x2+6x+x+3

2x2+7x+3 (2x2 means two x square)

if you want you can also multiply 2x+3 by x+3

like this:

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x(2x+1)+3(2x+1)

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2x2+7x+3 (2x2 means two x square)

They will both give you the same answer.

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3 years ago

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Answer:

$\frac{b^{-2}}{ab^{-3}}=\frac{b}{a}$

Step-by-step explanation:

Writing the description in algebraic translation

$\frac{b^{-2}}{ab^{-3}}$

so we have to find the expression which will be equal to $\frac{b^{-2}}{ab^{-3}}$ .

Considering the expression

$\frac{b^{-2}}{ab^{-3}}$

$\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}$

$\frac{b^{-2}}{b^{-3}}=b^{-2-\left(-3\right)}$

so the expression becomes

$=\frac{b^{-2-\left(-3\right)}}{a}$ ∵ $\frac{b^{-2}}{b^{-3}}=b^{-2-\left(-3\right)}$

$\mathrm{Subtract\:the\:numbers:}\:-2-\left(-3\right)=1$

$=\frac{b}{a}$

Therefore,

$\frac{b^{-2}}{ab^{-3}}=\frac{b}{a}$

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3 years ago

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