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3 years ago

What is the equation for a line with a slope of -1/3 and a y-intercept of -5?

Mathematics

1 answer:

garri49 [273]3 years ago

3 0

Answer:

y=-1/3x-5

Step-by-step explanation:

y=mx+b is equation of line where m is slope and b is y-intercept.

From question statement, we observe that

m= -1/3 , b= -5

put above values in equation of line, we get

y= -1/3x-5.

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Kyle started biking at a constant rate of 15 mph. Half an hour later, Kim followed on the same path at a constant rate of 18 mph

lidiya [134]

The answer is...

It would take kim approximately* dont know if I spelled it correctly* 2 hours 30 minutes to catch up with kyle.

4 0

4 years ago

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Please help me with this...

AURORKA [14]

Answer:

- 84 + 10i

Step-by-step explanation:

A complex number in standard form is a ± bi

a is the real part and bi the imaginary part

and $\sqrt{-1}$ = i

Given

$\sqrt{-100}$ - 84

= $\sqrt{100(-1)}$ - 84

= $\sqrt{100}$ × $\sqrt{-1}$ - 84

= 10i - 84

= - 84 + 10i ← in standard form

3 0

3 years ago

If a recipe calls for 0.800 kg of flour , about how many ounces of flour does it need? (1lb=16 oz, 1 lb = 0.454 kg )

stiks02 [169]

For this case we must take into account the following conversions of units:
1lb = 16 oz
1 lb = 0.454 kg
Applying the conversion of units we have:
(0.800) * (1 / 0.454) * (16/1) = 28.1938326
Rounding off we have:
28.2 oz
Answer:
it needs 28.2 oz of flour

8 0

3 years ago

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When a baseball is thrown upward, its height is a function of time. If this function is given by formula h(t)=−16t^2+24t+5, what

Harman [31]

Answer:

Step-by-step explanation:

If you graph out the parabola, you look for the maximum height of the parabola and it is 14.

6 0

3 years ago

An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

3 0

2 years ago