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bixtya [17]
3 years ago
11

What is the equation for a line with a slope of -1/3 and a y-intercept of -5?

Mathematics
1 answer:
garri49 [273]3 years ago
3 0

Answer:

y=-1/3x-5

Step-by-step explanation:

y=mx+b is equation of line where m is slope and b is y-intercept.

From question statement, we observe that

m= -1/3   ,  b= -5

put above values in equation of line, we get

y= -1/3x-5.

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6. Solve for the variable: 11x - 22 = -11x - 22
pentagon [3]
11x-22=-11x-22
11x+11x=-22+22
22x=0
x=0/22
x=0
Then the answer is option B
8 0
3 years ago
Read 2 more answers
Someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi. We think the
denpristay [2]

Answer:

The sample size must be greater than 37 if we want to reject the null hypothesis.

Step-by-step explanation:

We are given that someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi.

Also, we are given a level of significance of 5%.

Let \mu = <u><em>mean breaking strength of their climbing rope</em></u>

SO, Null Hypothesis, H_0 : \mu = 2,000 psi       {means that the mean breaking strength of their climbing rope is 2,000 psi}

Alternate Hypothesis, H_A : \mu < 2,000 psi      {means that the mean breaking strength of their climbing rope is lower than 2,000 psi}

Now, the test statistics that we will use here is One-sample z-test statistics as we know about population standard deviation;

                         T.S.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = ample mean strength = 1,997.2956 psi

            \sigma = population standard devaition = 10 psi

            n = sample size

Now, at the 5% level of significance, the z table gives a critical value of -1.645 for the left-tailed test.

So, to reject our null hypothesis our test statistics must be less than -1.645 as only then we have sufficient evidence to reject our null hypothesis.

SO,  T.S. < -1.645   {then reject null hypothesis}

         \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < -1.645

         \frac{1,997.2956-2,000}{\frac{10}{\sqrt{n} } } < -1.645

         (\frac{1,997.2956-2,000}{10}) \times {\sqrt{n} } } < -1.645

          -0.27044 \times \sqrt{n}< -1.645

               \sqrt{n}> \frac{-1.645}{-0.27044}

                 \sqrt{n}>6.083

                  n > 36.99 ≈ 37.

SO, the sample size must be greater than 37 if we want to reject the null hypothesis.

7 0
4 years ago
What is 12 time 27 please i need help please
mrs_skeptik [129]
324, hope this helps
6 0
3 years ago
Read 2 more answers
Combine like terms to simplify the expression: {\dfrac{2}{5}k-\dfrac35+\dfrac{1}{10}k} 5 2 ​ k− 5 3 ​ + 10 1 ​ kstart fraction,
Fed [463]

Given:

The expression is

{\dfrac{2}{5}k-\dfrac35+\dfrac{1}{10}k}

To find:

The simplified form of given expression.

Solution:

We have,

{\dfrac{2}{5}k-\dfrac35+\dfrac{1}{10}k}

On combining like terms, we get

=\left(\dfrac{2}{5}k+\dfrac{1}{10}k\right)-\dfrac{3}{5}

Taking LCM in the parenthesis, we get

=\left(\dfrac{4k+k}{10}\right)-\dfrac{3}{5}

=\left(\dfrac{5k}{10}\right)-\dfrac{3}{5}

=\dfrac{k}{2}-\dfrac{3}{5}

Therefore, the simplified form of the given expression is \dfrac{k}{2}-\dfrac{3}{5}.

7 0
3 years ago
2. Find the difference when -4n - 8 is subtracted from 2n + 5
Orlov [11]

Answer:

-6n - 13

Step-by-step explanation:

(-4n - 8) - (2n + 5)

Subtract -4n and 2n.

Then Add 8 and 5.

-6n - 13

3 0
3 years ago
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