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jasenka [17]
3 years ago
9

ANSWER ASAP!!!! Thank u

Mathematics
2 answers:
Vinvika [58]3 years ago
6 0

Answer: 20 cm

Step-by-step explanation:

a_sh-v [17]3 years ago
4 0

Answer:

27

Step-by-step explanation:

9 + 9 + 9 = 27

3 sides

I am sorry if this is wrong

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To frame two problems of linear equation in one variable of your choice and solve such that the result of the first problem shou
AVprozaik [17]

Answer:

x + y = 79 and

x - y = 25

(x,y) = (52,27)

Step-by-step explanation:

Let the variables be: x and y

The equations can be modelled as:

x + y = 79 and

x - y = 25

To solve for x and y, we have:

Make x the subject in x - y = 25

x = 25 + y

Substitute x = 25 + y in x + y = 79

25 + y + y = 79

25 + 2y = 79

Collect like terms

2y = 79 - 25

2y = 54

Divide both sides by 2

y = 27

Substitute y = 27 in x = 25 + y

x = 25 + 27

x = 52

So, we have:

(x,y) = (52,27)

8 0
3 years ago
PLEASE PLEASE I NEED HELP ON THIS ASAP
Alisiya [41]

Answer:

c

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{12},0)(± 12 ​ ,0)left parenthesis, plus min
lora16 [44]

Answer:

\mathbf{\dfrac{x^2}{49^2} +\dfrac{y^2}{37^2} =1}

Step-by-step explanation:

Given that :

the foci of the ellipse is (±√12,0) and C0-vertices are (0,±√37)

The foci are (-C,0) and (C ,0)

the focus has x-coordinates so the focus is  lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so C0-vertices are (0,±√37)

The given focus C = ae = √12

Given co-vertices ( minor axis) (0,±b) = (0,±√37)

b= √37

We can therefore express the  relation between the focus and semi major axes and semi minor axes as:

\mathbf{c^2 = a^2 - b^2 } \\ \\ \mathbf{a^2 = c^2 + b^2 } \\ \\ \mathbf{c^2 = ( \sqrt12)^2 - (\sqrt 37)^2 }  \\ \\ \mathbf{c^2 = 49 } \\ \\  \mathbf{c = \sqrt{49 }}

The equation of ellipse formula is:

\dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

and we know that \mathbf{a=\sqrt{49}  \ \  and  \  \ b=\sqrt{37}}

Thus ; the equation of the ellipse at the origin is

\mathbf{\dfrac{x^2}{49^2} +\dfrac{y^2}{37^2} =1}

3 0
4 years ago
An alloy is a mixture of metals. Suppose that a certain alloy is made by mixing 50 g of an alloy containing 12% copper with 78 g
givi [52]

Given :

An alloy is a mixture of metals. Suppose that a certain alloy is made by mixing 50 g of an alloy containing 12% copper with 78 g of an alloy containing 92% copper.

To Find :

How many grams of copper are in the resulting mixture what percentage of the resulting mixture is copper.

Solution :

Mass of copper in 50 gm alloy = 50\times 0.12 = 6\ gram.

Mass of copper in 78 gm alloy = 78\times 0.98 = 76.44\ gram.

Total mass of copper, ( 6 + 76.44 ) gm = 82.44 gram.

Percentage of copper in resulting mixture :

\%=\dfrac{82.44}{50+78}\\\\\%=64.4\ \%

Hence, this is the required solution.

8 0
4 years ago
A credit card company requires that its customers choose a 3 digit, numerical code to access their online account. Each digit sh
Citrus2011 [14]

Given :

A credit card company requires that its customers choose a 3 digit.

Each digit should be chosen from 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9.

So there are 10 possibilities for each digit.

To Find :

How many different three digit codes are there.

Solution :

We know, possibility of choosing each digit is 10.

So, total number of three digit codes are :

T=10\times 10\times 10\\\\T=1000

Therefore, their are 1000 different three digit codes.

Hence, this is the required solution.

4 0
3 years ago
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