Answer:
a) 0.0137060668
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I not know b part.
Explanation:
The perimeter of the track is the two circumferences of the semicircles (when combined, they form one circle, so we can just find the circumference of the circle) added to the lengths of the rectangle (
160
meters).
To find the circumference of the circle, we need to know the diameter.
Circumference of a circle:
d
π
or
2
r
π
, where
d
represents diameter and
r
represents radius
The diameter of the circle happens to be the same as the width of the rectangle. We know that the area of a rectangle is found by multiplying its length by its width. We know that the area is
14400
and that its length is
160
.
Width: area divided by length
14400
160
=
90
The diameter of the circle and the width of the rectangle is
90
meters.
Circumference:
90
⋅
π
=
90
π
→
If you are using an approximation such as 3.14 for
π
, multiply that by 90
Add
160
⋅
2
to the circumference since the lengths of the rectangle are also part of the perimeter.
160
⋅
2
=
320
90
π
+
320
i hope it helps you ok please mark ❣️ me as brainlist
Answer:
117
Step-by-step explanation:
The formula for a triangle is base times hight divided by two. So, 13 x 18 = 234, and 234/2 = 117
Answer:
Step-by-step explanation:
Answer
• A. Equation: 25(5 + x) = 325
,
• B. Answer: 8 dogs
Explanation
Given
• Charge to wash a dog: $25.
• She washed 5 dogs on Saturday and then some more on Sunday.
• She made $325 for the weekend.
Procedure
She charges $25 per wash, she made $325 for the weekend, and we know that on Saturday she washed 5 dogs, but we don't know how many she washed on Sunday. Thus, we have to build an equation in which the number of dogs washed on Sunday is represented by x (as we do not know the real number).
Considering that the total money made has to be equal to the multiplication of the charge times the dogs washed, the equation is:

Then, we have to solve for x to know how many dogs did she wash on Sunday.
0. Multiplying the parenthesis

<em>2. Subtracting 125 from both sides of the equation</em>


<em>3. Dividing both sides of the equation against 25</em>
