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NeTakaya
3 years ago
13

The initial points of a vector V are given.

Mathematics
1 answer:
slamgirl [31]3 years ago
7 0

Answer:

V=2i+6j

Step-by-step explanation:

vector V=4i+6j-(2i+0j)=2i+6j

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F(x) = 3x + 2 What is f(5)?
Ulleksa [173]

Answer:

if the equation if f(x) = 3x + 2, then f(5) would be equal to 3*5 + 2 = 17.

Step-by-step explanation:

8 0
3 years ago
How many lots of 10 second are there in 10 minutes
Vlad [161]

Answer:

60

Step-by-step explanation:

We can easily solve this by finding out how many 60 seconds are in 10 minutes, and then dividing by 10.

To do that, multiply 60 seconds by 10, since there are 60 seconds in each minute.

60*10=600. There are 600 seconds in ten minutes.

Now, divide by 10.

600/10=60

There are 60 intervals of 10 seconds in 10 minutes.

Hope this helps!

7 0
3 years ago
A company rents water tanks shaped like cylinders. Each tank has a radius of 6 feet and a height of 2 feet. The cost is $3 per c
choli [55]
It should be 36.00 dollars 

7 0
3 years ago
If the cubic function P(x) includes the points (−1, 0), (−2, 0), (3, 0), and (0, −12) which of the following represents this fun
zhannawk [14.2K]
I think the answer would be <span>2(x + 1)(x + 2)(x - 3).
Hope this helped! :) </span>
3 0
3 years ago
Figure ABCD is reflected across the x-axis. What are the coordinates of A' , B' , C' , and D' ? Enter your answer in each box.
stealth61 [152]

Answer:

The coordinates of ABCD after  the reflection across the x-axis would become:

  • A'(2, -3)
  • B'(5, -5)
  • C'(7, -3)
  • D'(5, -2)

Step-by-step explanation:

The rule of reflection implies that when we reflect a point, let say P(x, y), is reflected across the x-axis:

  • x-coordinate of the point does not change, but
  • y-coordinate of the point changes its sign

In other words:

The point P(x, y) after reflection across x-axis would be P'(x, -y)

P(x, y)        →       P'(x, -y)

Given the diagram, the points of the figure ABCD after the reflection across the x-axis would be as follows:

P(x, y)        →       P'(x, -y)

A(2, 3)       →       A'(2, -3)      

B(5, 5)       →       B'(5, -5)

C(7, 3)        →      C'(7, -3)

D(5, 2)       →       D'(5, -2)

Therefore, the coordinates of ABCD after  the reflection across the x-axis would become:

  • A'(2, -3)
  • B'(5, -5)
  • C'(7, -3)
  • D'(5, -2)

8 0
3 years ago
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