We have the following functions: f (x) = -3x ^ 4 - 14 g (x) = -x ^ 3 + 2f Deriving both functions we have: f '(x) = -12x ^ 3 g '(x) = -3x ^ 2 We equal zero and clear x: f '(x) = -12x ^ 3 = 0 ----> x = 0 g '(x) = -3x ^ 2 = 0 -----> x = 0 Substituting x = 0 in the given equations: f (0) = -3 (0) ^ 4 - 14 = -14 g (0) = - (0) ^ 3 + 2 = 2 Answer: the largest maximum y-value is: B.g (x)