Answer: Michael is 72.
hope this helps
Step-by-step explanation:
Let Brandon be b. Then Michael is 3g.
3g-18=9(b-18)
3g-18=9g-162
6g=144
b=24
3g=72
Answer:
x1=3 x2=-5
BUT x1=3 is not an answer because it doesnt respects the range on the original ecuation, so x2=-5 is the solution
Step-by-step explanation:
Answer:
Step-by-step explanation:
If diameter is 6 then the radius is half of that or 3.
A = pi * r^2
A = pi * 3^2
A = 9pi ft^2
For this case we must simplify the following expression:
![\sqrt [3] {\frac {12x ^ 2} {16y}}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B%5Cfrac%20%7B12x%20%5E%202%7D%20%7B16y%7D%7D)
We rewrite the expression as:
![\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\frac{\sqrt[3]{3x^2}}{\sqrt[3]{4y}}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B4%283x%5E2%29%7D%7B4%284y%29%7D%7D%3D%5C%5C%5Csqrt%5B3%5D%7B%5Cfrac%7B4%283x%5E2%29%7D%7B4%284y%29%7D%7D%3D%5C%5C%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%7D%7B%5Csqrt%5B3%5D%7B4y%7D%7D%3D)
We multiply the numerator and denominator by:
![(\sqrt[3]{4y})^2:\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{\sqrt[3]{4y}*(\sqrt[3]{4y})^2}=](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B4y%7D%29%5E2%3A%5C%5C%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B4y%7D%29%5E2%7D%7B%5Csqrt%5B3%5D%7B4y%7D%2A%28%5Csqrt%5B3%5D%7B4y%7D%29%5E2%7D%3D)
We use the rule of power
in the denominator:
![\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{(\sqrt[3]{4y})^3}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{4y}=](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B4y%7D%29%5E2%7D%7B%28%5Csqrt%5B3%5D%7B4y%7D%29%5E3%7D%3D%5C%5C%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B4y%7D%29%5E2%7D%7B4y%7D%3D)
Move the exponent within the radical:
![\frac{\sqrt[3]{3x^2}*(\sqrt[3]{16y^2}}{4y}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{2^3*(2y^2)}}{4y}=](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B16y%5E2%7D%7D%7B4y%7D%3D%5C%5C%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B2%5E3%2A%282y%5E2%29%7D%7D%7B4y%7D%3D)
![\frac{2\sqrt[3]{3x^2}*(\sqrt[3]{(2y^2)}}{4y}=\\\frac{2\sqrt[3]{6x^2*y^2}}{4y}=](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B%282y%5E2%29%7D%7D%7B4y%7D%3D%5C%5C%5Cfrac%7B2%5Csqrt%5B3%5D%7B6x%5E2%2Ay%5E2%7D%7D%7B4y%7D%3D)
![\frac{\sqrt[3]{6x^2*y^2}}{2y}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B6x%5E2%2Ay%5E2%7D%7D%7B2y%7D)
Answer:
Answer:
Therefore there revenue was $540,000.
Step-by-step explanation:
Let their total revenue last year be x
so
35% of x = $72,9000 - x
or, 35/100 × x = 729000 - x
or, 7x/20 = 729000-x
or, 7x = 20(729000-x)
or, 7x = 1458000- 20x
or, 7x + 20x = 14580000
or, 27x = 14580000
or, x = 14580000/27
so, x = $540,000
