If the data set represents the number of rings each person is wearing, being: 0,2,4,0,2,3,2,8,6, the interquartile range of the data is 2. Being, 4 as the Q1, 3 as the Q2 or median, and 6 as the Q3. Where the formula of getting the interquartile range is IQR= Q1-Q2.
squash = cordial + water
400 ml = 50 ml + x ml
350 ml = x ml
Therefore, 350 ml are water.
350 ml / 400 ml = 0.875 = 
So the answer is 7 / 8
The probability of finding one of the two defective fuses is:
The probability of finding 2 defective fuses is:
Therefore the probability of rejecting is 0.3117 + 0.026 = 0.3377.
Answer: See explanation
Step-by-step explanation:
Your question isn't really clear. Let me help you rephrase it and solve.
Let's say Cesar is creating a schedule to practice his instrument for band. He needs to practice for a total of 10 hours in a week. On Monday he practice for 1 1/2 hours, on Tuesday he practiced for 2 1/4 hours, and on Wednesday he practiced for 1 1/2 hours.
The total hours that Cesar has used in practicing will be:
= 1 1/2 + 2 1/4 + 1 1/2
= 5 1/4
To get the number of hours that Cesar need to practice during the rest of the week in order to have his 10 total hours, we subtract 5 1/4 hours from 10 hours. This will be:
= 10 - 5 1/4
= 4 3/4 hours.
Cesar needs to practice for 4 3/4 hours more.
