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sashaice [31]
3 years ago
15

PLS HELP ASAP!!!!!!!!!!!!! Solve for x.

Mathematics
1 answer:
Damm [24]3 years ago
8 0
The answer is number 2
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3.
Leya [2.2K]

Answer:

Step-by-step explanation:

I dont know sorry

8 0
3 years ago
Able
olasank [31]

Answer:

1/4

Step-by-step explanation:

.5/2=.25=1/4

4 0
3 years ago
24. What term describes a transformation that does
goldenfox [79]

Rigid Motion

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Find the equation (in terms of x) of the line through the points (-2,3) and (4,-9)<br> y =
shepuryov [24]

Answer:

y =5

Step-by-step explanation:

m=

−9−7

5−5

=

−16

0

=0

y=mx+b

5=(0)(7)+b

b=5

therefore y = 5

3 0
3 years ago
Read 2 more answers
The question I need is question #13. Please provide a step by step answer. Thank You
Jet001 [13]

Answer:

Step-by-step explanation:

We have plane 1 flying SW for 4 hours at a rate of 415 mph.  The distance he covers using the d = rt formula for distance, is 415(4) = 160 miles.

We also have plane 2 flying directly east (along the x-axis) for 4 hours at 327 mph.  The distance he covers using the d = rt formula for distance, is 327(4) = 1308 miles.  The angle in between them at this point is 135 degrees, and what we need to find is the length of the vector connecting the 2 planes.  IF this was right triangle trig that distance would be the hypotenuse and we could solve for it using Pythagorean's Theorem.  BUT it is NOT a right triangle, so we have to find some other means with which to solve for that length.  We will use the Law of Cosines to do this.

?^2=1660^2+1308^2-2(1660)(1308)cos(135) which simplifies a bit to

?^2=2755600+1712864-(-3070653.624)

If you add all of that together, you'll get

?^2=7537117.624  and you'll take the square root of that to get that the distance between the 2 planes after 4 hours is

2745 miles

4 0
3 years ago
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