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Crank
4 years ago
14

X/5=3 A)3/5 B)1/5 C)15 D)5/3

Mathematics
2 answers:
Butoxors [25]4 years ago
8 0
15 is the answer hope it helps!
valentinak56 [21]4 years ago
5 0
X/5=3  multiply both sides by 5

x=15
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You pick a card at random. 6 7 8 9 What is P(not 9)? Write your answer as a percentage. %
Harman [31]

Answer:

75%

Step-by-step explanation:

You pick a card at random. 6 7 8 9 What is P(not 9)? Write your answer as a percentage. %

Given the following

Total cards = 4 (6,7,8,9)

If the card is not 9, the required card will be (6,7,8)

Number of cards that are not 9 is 3

Probability = expected/total

Pr(not 9) = 3/4

express as percent

Pr(not 9) = 3/4×100

Pr(not 9) = 75%

4 0
3 years ago
In the accompanying diagram, what is sin E? A. B. E C. D. 4 G A B С OD​
IRINA_888 [86]

Answer:

Sin(E) = \frac{4}{5}

Step-by-step explanation:

The full question is as follows :

To find - In the accompanying diagram, what is sin E?

Proof -

We know that,

Sin(theta) = (opposite side) / (hypotenuse)

From the diagram, we can see that,

Base = 3

Perpendicular = 5

Hypotenuse = 5

So,

For angle E,

Opposite side = 4

Hypotenuse = 4

∴ we get

Sin(E) = \frac{4}{5}

5 0
3 years ago
Which value could go in the blank cell so that the percentage of only children that
babunello [35]

Answer:

maybe B

I am not to my answer

8 0
3 years ago
Solve equation 9.6=1.2b
Molodets [167]
Divide. b=9.6/1.2. b=8.
5 0
4 years ago
Read 2 more answers
It is known that x1 and x2 are roots of the equation 3x^2+2x+k=0, where 2x1=−3x2. Find k.
miss Akunina [59]

Answer:

k = 8

Step-by-step explanation:

Since the roots of the equation 3x² + 2x + k are x₁ and x₂ and 2x₁ = 3x₂.

By the roots of an equation, ax² + bx + c , where its roots are  x₁ and x₂. It follows that sum of roots are x₁ + x₂ = -b/a and product of roots are x₁x₂ = c/a.

Comparing both equations, a = 3 b = 2 and c = k.

So, x₁ + x₂ = -b/a = -2/3 and x₁x₂ = c/a = k/3

x₁ + x₂ = -2/3 and x₁x₂ = k/3

3x₁ + 3x₂ = -2 (1) and 3x₁x₂ = k  (2)

Since 2x₁ = -3x₂, and -2x₁ = 3x₂substituting this into equations (1) and (2) above, we have

3x₁ + 3x₂ = -2 (1) and 3x₁x₂ = k  (2)

3x₁ + (-2x₁) = -2  and x₁(3x₂) = k

3x₁ - 2x₁ = -2  and x₁(3x₂) = k  

x₁ = -2  and x₁(-2x₁) = k  

x₁ = -2  and -2x₁² = k  

Substituting x₁ = -2 into -2x₁² = k, we have

-2x₁² = k

-2(-2)² = k

2(4) = k

8 = k

So, k = 8

7 0
4 years ago
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