Step-by-step explanation:
The correct answer here is 51
|r+3| = (r+3) when r ≥ -3 so for r ≥ -3
r + 3 ≥ 7
r ≥ 4
|r+3| = -(r+3) when r < -3 so for r < -3
-(r + 3) ≥ 7
r + 3 ≤ -7
r ≤ -10
The answer to this question is r ≤ -10, r ≥ 4
Answer:
3a:20d+35
3b:35u+49q+56
4a:15+20t
4b:96k+120t+84
5a:24t+108m+60
5b:56q+28b+35
6a:14q+10w+24
6b:54v+99+27t
7a:16g+24+24c
7b:30a+55+50d
(i think thats what they are but the picture is small so its kind of hard to see)
Step-by-step explanation:
(since theres 10 total ill just give an example on how i solved 5a)
5(4d+7)
simplify into: (5•4d)+(5•7)
multiply: (20d)+(35)
since you do not know what d is, you cannot add them
remove parentheses once done:20d+35
(you don't need parentheses since multiplication come before addition but its easier to just use them)
<h2>Hope this helps</h2>
