1. Using your straightedge, draw a reference line, if one is not provided.
2. Copy the side of the square onto the reference line, starting at a point labeled A'.
3. Construct a perpendicular at point B' to the line through ab2.
4. Place your compass point at B', and copy the side of the square onto the perpendicular b'g. Label the end of the segment copy as point C.
5. With your compass still set at a span representing AB, place the compass point at C and swing an arc to the left.
6. Holding this same span, place the compass point at A' and swing an arc intersecting with the previous arc. Label the point of intersection as D.
7. Connect points A' to D, D to C, and C to B' to form a square.
Answer:
The numbers:
1, -3, 2, -9, 3, -15, 4, -21,
are not linear.
Step-by-step explanation:
If it was linear:
4, 3, 2, 1, -3, -9, -15, -21
Respuesta: Uno
La suma de la probabilidad de todos los resultados posibles de un experimento aleatorio debe ser igual a uno.
Porque algunos resultados más ocurren en cada sendero y la suma de todas las probabilidades es 100% o uno.
Espero haber ayudado, buena suerte! :)
If you're factoring, your answer is
(4x - 3)(4x + 5)
You'll work it out this way:
16x^2 + 8x - 15
Since there's no GCF here, you multiply the first and third terms, giving you -240. Your next step is to find two numbers that have a sum of 8 and a product of -240. These numbers are 20 and -12. Plug those in and you've got:
16x^2 + 20x - 12x - 15
From here you divide it into two binomials. These are (16x^2 + 20x) and (-12x - 15).
When you take out the greatest common factors (4x and -3), they become:
4x(4x + 5) - 3(4x + 5)
Then you group what's outside of the parentheses together (4x - 3)
And bring what's inside of the parentheses down (4x + 5).
This brings your answer to
(4x - 3)(4x + 5)
I would use the quadratic formula for this:
x = -b ± √b² - 4ac over 2a
x = 8 ± √64 - 4(1)(0) over 2(1)
x = 8 ± √64 over 2
x = 8 <span>± 8 over 2 [simplify]
x = 4 </span><span>± 4
x1 = 4 + 4 x2 = 4 - 4
x1 = 8 x2 = 0
Thus, the solutions for x would be 0 and 8.</span>
