Y=3x^2. -12x+6
If x= 0 then y= 3•0^2 -12•0+6=6
X=0, y=6
y intercept is the place where the curve touches the y-axis and is at point (0, 6)
Answer:
the solutions are (3, 7) and (-1, -1)
Step-by-step explanation:
Insert the " = " symbol between the two equations, obtaining:
y = x^2 - 2 = y = 2x + 1
Then x^2 - 2 = 2x + 1, or
x^2 - 2x - 3 = 0, and this can be factored into (x - 3)(x + 1) = 0.
Thus, the x values that satisfy this system are {-1, 3}.
Use y = 2x + 1 to find the corresponding y values:
y = 2(-1) + 1 = -1
and
y = 2(3) + 1 = 7
Then the solutions are (3, 7) and (-1, -1)
Answer: On the 29th day
Step-by-step explanation:
According to this problem, no lilypad dies and the lilypads always reproduce, so we can apply the following reasoning.
On the first day there is only 1 lilypad in the pond. On the second day, the lilypad from the first reproduces, so there are 2 lilypads. On day 3, the 2 lilypads from the second day reproduce, so there are 2×2=4 lilypads. Similarly, on day 4 there are 8 lilypads. Following this pattern, on day 30 there are 2×N lilypads, where N is the number of lilypads on day 29.
The pond is full on the 30th day, when there are 2×N lilypads, so it is half-full when it has N lilypads, that is, on the 29th day. Actually, there are 
lilypads on the 30th, and 
lilypads on the 29th. This can be deduced multiplying succesively by 2.
Answer:
x = pi, 3pi, 5pi etc
x = -pi, -3pi, -5pi etc
Step-by-step explanation:
cos^2 x + 2 cos x + 1 = 0
replace cos x with m
m^2 + 2m +1 = 0
solve by factoring (this is a^2 +2ab+b^2 = (a+b)^2 where a =m and b=1)
(m+1)^2=0
take the square root of each side
m+1 =0
m=-1
now replace m with cos x
cos x = -1
take arccos of each side
arccos cos x = arccos (-1)
x = pi, 3pi, 5pi etc
Answer:
<h2>N = 68°</h2>
Step-by-step explanation:
Since ∆LMM is a triangle all it's interior angles sum up to 180°
To find M add up all the angles and N and equate it to 180° to find N
That's
L + M + N = 180
33 + N + 79 = 180
N + 112 = 180
N = 180 - 112
We have the final answer as
<h3>N = 68°</h3>
Hope this helps you
