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Vsevolod [243]
2 years ago
12

Write an expression to represent: 8 less than the product of 3 and a number.

Mathematics
1 answer:
DanielleElmas [232]2 years ago
5 0
The answer would be 3n - 8
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Can someone help me find the area of this circle and round to the nearest tenth
larisa [96]

the circle has a diameter of 12, thus its radius is half that, or 6.


\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=6 \end{cases}\implies A=\pi 6^2\implies A=36\pi \\\\\\ A \approx 113.0973355\implies A=\stackrel{\textit{rounded up}}{113.1}

8 0
3 years ago
Which transformation would transform the shaded figure onto the unshaded figure????
Rzqust [24]

Answer: A dilation

Step-by-step explanation:

A dilation is when you change the scale factor of an object to take up more or less space to it into the desired area.

5 0
3 years ago
Read 2 more answers
PLEASE HELP! WILL GIVE BRAINLIEST!
Anton [14]

Answer:

Graph the function and its parent function. Then describe the transformation. 7.9(x) = x + 4. 8. f(x) = x - 6. 4. 8 x. -4. 48 x ... Write a function g whose graph represents the indicated transformation of the graph of f. ... 96)= 14x+31+2 -2 = 14x+3| ... 33. f(x) = x; translation 3 units down followed by a vertical shrink by a factor of.

Step-by-step explanation:

Hope this helps!

6 0
3 years ago
Can somebody help me with this?
icang [17]

We are given polynomial: 5x^3+8x^2-7x-6.

We need to explain why the binomial (x + 2) IS a factor of this polynomial expression and  why the binomial (x + 1) IS NOT a factor of this polynomial expression.

Let us set first factor equal to 0 and solve for x.

x+2=0

x=-2.

Plugging x=-2 in given polynomial, we get

5(-2)^3+8(-2)^2-7(-2)-6 = 5(-8) +8(4)+14-6

= -40 +32+14-6

=0

<em>Because x=-2 gives 0 on plugging in given polynomial, so it's factor of given polynomial expression.</em>

Now, let us check second factor x+1=0

x=-1.

Plugging x=-1 in given polynomial, we get

5(-1)^3+8(-1)^2-7(-1)-6 = 5(-1) +8(1)+7-6

=-5+8+7-6.

= -4.

<em>Because x=-1 doesn't gives 0 on plugging in given polynomial, so it's not a factor of given polynomial expression.</em>

7 0
2 years ago
Use the surface integral in​ Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus
Tom [10]

Stokes' theorem says the integral of the curl of \vec F over a surface S with boundary C is equal to the integral of \vec F along the boundary. In other words, the flux of the curl of the vector field is equal to the circulation of the field, such that

\displaystyle\iint_S\nabla\times\vec F\cdot\mathrm d\vec S=\int_C\vec F\cdot\mathrm d\vec r

We have

\vec F(x,y,z)=x^2\,\vec\imath+4x\,\vec\jmath+z^2\,\vec k

\implies\nabla\times\vec F(x,y,z)=4\,\vec k

Parameterize the ellipse S by

\vec s(u,v)=\dfrac{u\cos v}{\sqrt5}\,\vec\imath+\dfrac{u\sqrt5\sin v}4\,\vec\jmath

with 0\le u\le1 and 0\le v\le2\pi.

Take the normal vector to S to be

\dfrac{\partial\vec s}{\partial\vec u}\times\dfrac{\partial\vec s}{\partial\vec v}=\dfrac u4\,\vec k

Then the flux of the curl is

\displaystyle\iint_S4\,\vec k\cdot\dfrac u4\,\vec k\,\mathrm dA=\int_0^{2\pi}\int_0^1u\,\mathrm du\,\mathrm dv=\boxed{\pi}

4 0
3 years ago
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