Answer of what is the length is 12. if we add all the sides it has to come as 36,so if length=x then width=2x therefore X+X+2X+2X=36 therefore x=6 then width=2x =12.
The law of cosines for this particular situation is b^2 = a^2 + c^2 - 2ac cosB.
Filling in what you know, you have b^2 = 25 + 49 - [2(5)(7)-.1908], which simplifies to b^2 = 74 - 69.8092 which gives you a b^2 value of 4.1908, but you have to take the square root of that so you get a side value for b of 2.05.
Cos = adjacent over hypotenuse
cos33 = b/170
170cos33 = b
b = 142.574 inches
Answer: the width of the uniform path is 9 meters.
Step-by-step explanation:
Let x represent the width of the uniform path.
A pool measuring 18 meters by 22 meters is surrounded by a path of uniform width. It means that the combined length of the pool and the uniform path is (18 + 2x) meters and the combined width of the pool and the uniform path is (22 + 2x) meters.
If the area of the pool and the path combined is 1440 square meters, it means that
(18 + 2x)(22 + 2x) = 1440
396 + 36x + 44x + 4x² = 1440
4x² + 80x + 396 - 1440 = 0
4x² + 80x - 1044 = 0
Dividing both sides of the equation by 4, it becomes
x² + 20x - 261 = 0
x² + 29x - 9x - 261 = 0
x(x + 29) - 9(x + 29) = 0
x - 9 = 0 or x + 29 = 0
x = 9 or x = 29
Since the width cannot be negative, then x = 9 meters
Sound travels 10200m farther through stone in 17 seconds than through aluminium
Speed of sound in aluminium = 3100 m/s
The speed of sound in stone = 3700 m/s
Time taken = 17 minutes
Distance traveled = Speed x Time
Distance traveled by sound in aluminium in 17 seconds = 3100 x 17
Distance traveled by sound in aluminium in 17 seconds = 52700 m
Distance traveled by sound in stone in 17 seconds = 3700 x 17
Distance traveled by sound in stone in 17 seconds = 62900 m
Difference in the distance traveled = 62900 - 52700
Difference in the distance traveled = 10200 m
Sound travels 10200m farther through stone in 17 seconds than through aluminium
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