Answer:
m < EAD = 29 degrees
m < CAB = 119 degrees
Given :
The question states that m < CAE = m<FAB = 61 degrees and m<DAF = 90 degrees
Solution:
1. Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)
2. m<BAC + m<EAC = 180 degrees (sum of linear pair)
3. m<CAB = 180 degrees - m<EAC
4. Equation 1: m<CAB = m<EAF = 119 degrees
5. m<EAF = m<EAD + m< DAF
6. m<EAD = m<EAF - m<DAF
7. m<EAD = 119 degrees-90 degrees = 29 degrees
Hope this helps!!! :)
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30 000 + 7 000 + 800 + 30 + 1
Answer:
-12x + 94
Step-by-step explanation:
Simplify:







Answer:
Give it a bit of time OK I will say the answer is in the *c'h_a-t
(3x^2+5x-2)- ((2-x^2+2x+5))
(3x^2+5x-2)- ((7-x^2+2x))
Since no more can be added or broken down
3x^2+5x-2 - 7-x^2+2x
2x^2+7x-9