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JulsSmile [24]
3 years ago
8

two dice are rolled until a sum of either 5 or 7 occurs. estimate the probability that a 5 occurs first g

Mathematics
1 answer:
Ierofanga [76]3 years ago
6 0

Answer:

The correct answer is "\frac{2}{5}". A further solution is provided below.

Step-by-step explanation:

According to the question,

The probability of getting a 5 will be:

= \frac{4}{36}

= \frac{1}{9}

The probability of getting a 7 will be:

= \frac{6}{36}

= \frac{1}{6}

The probability of not a 5 nor a 7 will be:

= 1-[\frac{4}{36} +\frac{4}{36} ]

= \frac{26}{36}

= \frac{13}{18}

Now,

For roll of 2 dice,

⇒ P=\frac{1}{9} +{\frac{1}{9}\times (\frac{13}{18} ) }+{(\frac{1}{9} )\times (\frac{13}{18} )^2}+{\frac{1}{9}\times (\frac{13}{18} )^3 }+...

        =\frac{1}{9} [1+\frac{13}{18} +\frac{13^2}{18^2} +\frac{13^3}{18^3} +...]

        =\frac{1}{9} [\frac{1}{1-\frac{13}{18} } ]

        =\frac{1}{9} [{\frac{1}{\frac{5}{8} } ]

        =\frac{2}{5}

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