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barxatty [35]
3 years ago
13

The coordinates P(0, 1), Q(3, 2), R(5, -4) form a right triangle.

Mathematics
1 answer:
Arisa [49]3 years ago
4 0

Answer:

Yes it forms a right angle triangle.

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Olin [163]
The answer should be 24 square units.

5 is the hypotenuse and the one we need is the base and the height. They gave us the height, which was 6 in total but 3 for the triangle. But we needed to find the base.

In order to do that, we need to use the Pythagorean Theorem.

a^2+b^2=c^2

3^2+b^2=5^2

9+b^2=25

Subtract 9 from both sides

b^2=16

Then square root both sides.

b=4.

Now that we have the base, you can then find the area of the triangle.

BH/2
4*3/2
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3 years ago
In the given diagram if AB || CD, ∠ABO = 118° , ∠BOD = 152° , then find the value of ∠ODC.
GaryK [48]

Answer:

90°

Step-by-step explanation:

Through point O draw a ray on left side of O which is || to AB & CD and take any point P on it.

Therefore,

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118° + ∠BOP = 180°

∠BOP = 180° - 118°

∠BOP = 62°.... (1)

Since, ∠BOP + ∠POD = ∠BOD

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∠POD = 152° - 62°

∠POD = 90°.....(2)

∠POD + ∠ODC = 180° (by interior angle Postulate)

90° + ∠ODC = 180°

∠ODC = 180° - 90°

\huge\red {\boxed {m\angle ODC =  90°}}

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GarryVolchara [31]
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