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3 years ago

Solve for q tysm:)))

Mathematics

2 answers:

statuscvo [17]3 years ago

8 0

Answer:

Step-by-step explanation:

givi [52]3 years ago

5 0

<h3><u>Question</u></h3>

Solve for q

-----------------

$(8q-5)^o+81=180^o$

$8q-5+81=180$

$8q+76=180$

$8q=180-76$

$8y=104$

$q=13$

---------------

<h3><u>Answer</u></h3>

<u /> $q=13$

<h3><u>-----------------------</u></h3><h3><u>hope it helps...</u></h3><h3><u>have a great day!!</u></h3>

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In the figure below, angle y and angle x form vertical angles. Angle y forms a straight line with the 60° angle and the 70° angl

Dmitry_Shevchenko [17]

<u>Answer:</u>

The value of x is 50°.

<u>Step-by-step explanation:</u>

x = y
2(70 + 60) + x + y = 360

2(130) + x + x = 360
=> 260 + 2x = 360
=> 2x = 360 - 260
=> 2x = 100
=> x = 50

Hence, <u>the value of x is 50°.</u>

Hoped this helped.

$BrainiacUser1357$

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2 years ago

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A triangle has an area of 78 square inches. Its base is measured to be 13 inches. What is the height of this triangle in inches?

Fynjy0 [20]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{12 \: inches}}}}}$

Step-by-step explanation:

Given,

Area of a triangle = 78 square inches

Base of a triangle = 13 inches

Height of a triangle = ?

<u>Finding</u><u> </u><u>the</u><u> </u><u>height</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>triangle</u>

$\boxed{ \sf{area \: of \: a \: triangle = \frac{1}{2} \times \: base \: \times \: height}}$

$\dashrightarrow{ \sf{78 = \frac{1}{2} \times 13 \times h}}$

$\dashrightarrow{ \sf{78 = 6.5 \: h \: }}$

$\dashrightarrow{ \sf{6.5 \: h = 78}}$

$\dashrightarrow{ \sf{ \frac{6.5h}{6.5} = \frac{78}{6.5}}}$

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Hope I helped!

Best regards! :D

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3 years ago

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3 years ago

Please also show the steps to get the answer

Natasha_Volkova [10]

Answer:

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Step-by-step explanation:

Angle S is 95 so arc QR = 95×2 = 190

Total arc is 360 degree

Now to find arc QS

arc QS + arc SR + arc QR =360

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3 years ago

What is 0.37 divided by 5.18

Contact [7]

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Step-by-step explanation:

5.18÷0.37=14

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Solve for q tysm:)))​

Solve for q tysm:)))