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4 years ago

Rewrite in simplest radical form 1/x^-3/6.

Mathematics

1 answer:

Aneli [31]4 years ago

6 0

$\cfrac{1}{x^{- \frac{3}{6} }} = \cfrac{1}{x^{- \frac{1}{2} }} =x^{ \frac{1}{2} }= \sqrt{x}$

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Please help me with this answer

sweet [91]

x = visiting

x+14 = home

2x + 14 = 44

2x = 30

x = 15

15 + 14 = 29

home team had 29 fans

5 0

3 years ago

Point x is located at (-3,-4) and point Y is located at (6,-4). What is the distance between these two points?

mart [117]

Answer:

Step-by-step explanation:

Distance between two points is given as;

Square root [(X2-x1) 2+ (y2-y1)2]

= (6-(-3))2 +(-4-(-4))2

=Square root (81 +0)

7 0

4 years ago

I need help with this this is hard

saveliy_v [14]

Answer:

n > -6 and n < 8! Heart it if it was helpful :D

Step-by-step explanation:

Okay! So n has to be bigger than -6, but smaller than 8. So the inequalities are n > -6 and n < 8!

8 0

3 years ago

Read 2 more answers

An arithmetic sequence is represented by the recursive formula a1=17an=an−1−8 . What is the fourth term in the sequence? a4=−4 a

user100 [1]

Answer:

a₄ = - 15

Step-by-step explanation:

Using the recursive formula and a₁ = 17 , then

a₂ = a₁ - 8 = 17 - 8 = 9

a₃ = a₂ - 8 = 9 - 8 = 1

a₃ = a₂ - 8 = 1 - 8 = - 7

a₄ = a₃ - 8 = - 7 - 8 = - 15

4 0

3 years ago

How much more would $8,000 earn in four years compounded daily at 5% than compounded annually at 5%?

QveST [7]

Answer:

Given the statement:

8,000 earn in four years compounded daily at 5%

To find the amount we use formula:

$A = P(1+\frac{r}{n})^{nt}$

where P is the principal , A is the amount , n is number of times compounded per year and t is the time in year.

Here, Principal(P) = $8000, r = 5% and n = 365

Substitute these given values we get;

$A_1= 8000(1+\frac{5}{365})^{365 \cdot 4}$

$A_1= 8000 \cdot 1.000137^{1460}$

$A_1= 8000 \cdot 1.22141$

Simplify:

$A_1= \$9771.28$

To find the Interest we use formula:

$I_1= A_1-P$

$I_1= 9771.28 -8000 = \$1771.28$

It is also given that:

8,000 earn in four years compounded annually at 5%.

Here, P = $8000, r = 5% , t =4 year and n = 1

Using the same formula to calculate the amount:

$A_2 = 8000(1+\frac{5}{1})^{1 \cdot 4}$

$A_2= 8000(1.05)^4$

Simplify:

$A_2= \$9724.05$

To find the Interest :

$I_2= A_2 - P$

$I_2= 9724.05 - 8000= \$1724.05$

Then;

$I_1-I_2 = 1771.28-1724.05 = \$47.23$

Therefore, $47.23 more would $8,000 earn in four years compounded daily at 5% than compounded annually at 5%

6 0

4 years ago