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3 years ago

Rewrite in simplest radical form 1/x^-3/6.

Mathematics

1 answer:

Aneli [31]3 years ago

6 0

$\cfrac{1}{x^{- \frac{3}{6} }} = \cfrac{1}{x^{- \frac{1}{2} }} =x^{ \frac{1}{2} }= \sqrt{x}$

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sesenic [268]

Answer:

x=1, x=-4

Two distinct real roots

Step-by-step explanation:

x² + 3x- 4 = (x - 1)(x + 4)

x=1, x=-4

Two distinct real roots

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3 years ago

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mars1129 [50]

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10=c+d<br> c is one more than d <br> what is the value of c?<br>with working out

Leya [2.2K]

C= 5.5 I'm pretty sure that's the answer

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3 years ago

How do you Simplify :(2p^-3)^5

iragen [17]

Answer:

The final simplification is (32p^-15).

Step-by-step explanation:

Given:

(2p^-3)^5 we have to simplify.

Property to be used:(Power rule)

Power rule states that: $(a^x)^y=a^x^y$ ...the exponents were multiplied.

Using power rule.

We have,

⇒ $(2p^-3)^5$

⇒ $(2^5)(p^-3^*5)$ ...taking exponents individually.

⇒ $32(p^-^1^5)$ ... $2^5=2*2*2*2*2=32$

⇒ $32p^-^1^5$

So our final values are 32p^-15

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3 years ago

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