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3 years ago

Need help ASAP highschool level math

Mathematics

2 answers:

krok68 [10]3 years ago

8 0

Answer:

cool

Step-by-step explanation:

i couldn't care less

enot [183]3 years ago

3 0

Answer:

The solution for the system of equations is (2, 4). This means that for February, both the number of imports and the number of exports was 4.

Step-by-step explanation:

Again, remember that the solutions for a system, in this case two charts, are where the outputs (exports) are the same.

We can see that the exports for both f(x) and g(x) are the same for the month of February (second month).

This means that the solution to our system of equations is (2, 4).

So, the solution means that for the second month February, the number of imports was equivalent to the number of exports: both are 4.

(And lastly, out of the four months given, only February had the same number of imports and exports.)

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A picture frame is 9 inches long and 6 inches wide. It can display a picture 6 inches long and 4 inches wide. What is the area o

irina1246 [14]

Answer:

30 inches squared

Step-by-step explanation:

First, find the area of the entire frame using length times height. 9*6 is 54 inches squared. Then, find the area of the middle space the same way. 6*4 is 24 inches squared. Lastly, subtract the middle from the entire frame's area. 54-24 is 30 inches squared.

4 0

3 years ago

Which is larger?<br> 7% or 0.7 and explain how you know.

disa [49]

They are equal because you can measure the percentage as a decimal with a maximum of 1.

7 0

3 years ago

Read 2 more answers

Helpppppp$$$!!!!!!!!!!!!!!!!! Plz

insens350 [35]

9514 1404 393

Answer:

Step-by-step explanation:

Given the triangle congruence statements, the segment and angle congruence statements must refer to corresponding vertices. Corresponding vertices are listed in the same order in the triangle congruence statement.

The one FALSE statement in the bunch is ...

$\overline{OD}\cong\overline{AL}$

The true statements for these segments would be ...

$\overline{OD}\cong\overline{JL}\\\\\overline{CD}\cong\overline{AL}$

5 0

3 years ago

A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so

Debora [2.8K]

Let $A(t)$ = amount of salt (in pounds) in the tank at time $t$ (in minutes). Then $A(0) = 11$ .

Salt flows in at a rate

$\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}$

and flows out at a rate

$\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}$

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

$\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}$

which I'll solve with the integrating factor method.

$\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95$

$-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}$

$\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}$

Integrate both sides. By the fundamental theorem of calculus,

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}$

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)$

$\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}$

$\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}$

$\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}$

After 1 hour = 60 minutes, the tank will contain

$A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131$

pounds of salt.

7 0

2 years ago

Choose all that give the correct equation of the line parallel or perpendicular to the given line passing through the point.

andriy [413]

Answer:

A and B

Step-by-step explanation:

Parallel lines are lines which have the same slope. Perpendicular lines have negative reciprocal slopes.

For the options:

A. Both equations have 7/5 as the slope. They are parallel.

B. The slopes are 1 and -1. These are perpendicular.

C. The slopes are 9/2 and are parallel.

D. The slopes are 7/3 and -3/7. They are perpendicular.

The solution is A and B.

7 0

3 years ago