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N76 [4]
2 years ago
7

Solve for x. 13 =(5x+ 6)/8 + (5x+4)/4

Mathematics
1 answer:
valkas [14]2 years ago
3 0

Answer: x=6

Step-by-step explanation:

To solve for x, we want to isolate the variable.

\frac{5x+6}{8} +\frac{5x+4}{4} =13        [get common denominator]

\frac{5x+6}{8} +\frac{2(5x+4)}{8} =13     [add fractions]

\frac{5x+6+10x+8}{y} =13          [combine like terms]

\frac{15x+14}{8} =13                 [multiply both sides by 8]

15x+14=104            [subtract both sides by 14]

15x=90\\                      [divide both sides by 15]

x=6

Now, we know that x=6.

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Put a check by all the factors of 20.
Degger [83]
1,2,4,5,10,20 are all factors of 20. (To be extra sure you can ask google too).
3 0
3 years ago
Two companies offer jane sales position. Company a pays $3,000 per month plus $250 per car sold.. Company B pays 2,500 per month
Montano1993 [528]

Given :

Two companies offer jane sales position. Company a pays $3,000 per month plus $250 per car sold.. Company B pays 2,500 per month plus $350 per car sold.

To Find :

Which equation could be used to determine the number of cars sold in a month, x, that would result in the same total income from each company.

Solution :

Let, x car are sold for same income.

Mathematical equation of company one :

T_1 =3000+250x

Mathematical equation of company two :

T_2 =2500+350x

For same income :

T_1=T_2\\\\3000 + 250x = 2500 + 350x\\\\100x = 500\\\\x=5

So, for same total income from each company the number of cars sold in a month should be 5.

Hence, this is the required solution.

3 0
3 years ago
PLEASE HELP I'LL LEAVE THANKS:)
miskamm [114]
1 to 6!!!!!!!!!!!!!!!!!!
8 0
3 years ago
How can you know if this equation is true? 1/2 + 3/8 = 4/10 = 2/5
romanna [79]

Answer:

<h2>2. Because 25<12, this equation can not be true.</h2>

Step-by-step explanation:

I just solved the equation and 1/2 + 3/8 = 7/8 or 87.5%.

4/10 equals 40%.

Since these two do not sync up, the equation must be false and 2 is the only answer saying the equation is false.

I'm always happy to help :)

3 0
3 years ago
A test consists of 20 problems and students are told to answer any 10 of these questions. In how many different ways can they ch
Furkat [3]
We must find UNIQUE combinations because choosing a,b,c,d... is the same as d,c,b,a...etc.  For this type of problem you use the "n choose k" formula...

n!/(k!(n-k)!), n=total number of choices available, k=number of choices made..

In this case:

20!/(10!(20-10)!)

20!/(10!*10!)

184756
3 0
3 years ago
Read 2 more answers
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